Answer: the average velocity decreases
Explanation:
From the provided data we have:
Vessel avg. diameter[mm] number
Aorta 25.0 1
Arteries 4.0 159
Arteioles 0.06 1.4*10^7
Capillaries 0.012 2.9*10^9
from the information, let 
be the mass flow rate, 
is density, n number of vessels, and A is the cross-section area for each vessel
the flow rate is constant so it is equal for all vessels,
The average velocity is related to the flow rate by:
we clear the side where v is in:
area is π*R^2 where R is the average radius of the vessel (diameter/2)
we get:
you can directly see in the last equation that if we go from the aorta to the capillaries, the number of vessels is going to increase ( n will increase and R is going to decrease ) . From the table, R is significantly smaller in magnitude orders than n, therefore, it wont impact the results as much as n. On the other hand, n will change from 1 to 2.9 giga vessels which will dramatically reduce the average blood velocity
Answer:
T(water)=50.32℃
T(air)=3052.6℃
Explanation:
Hello!
To solve this problem we must use the equation that defines the transfer of heat by convection, which consists of the transport of heat through fluids in this case water and air.
The equation is as follows!
Q = heat
h = heat transfer coefficient
Ts = surface temperature
T = fluid temperature
a = heat transfer area
The surface area of a cylinder is calculated as follows
Where
D=diameter=20mm=0.02m
L=leght=200mm)0.2m
solving
For water
Q=2Kw=2000W
h=5000W/m2K
a=0.01319m^2
Tα=20C
solving for ts
for air
Q=2Kw=2000W
h=50W/m2K
a=0.01319m^2
Tα=20C
Answer:
The answer is option
C . the JFET has a PN junction
Explanation:
Not only is option C in the question a dissimilarity between the MOSFET and the JFET we can go on with some more dissimilarities.
1.MOSFET stands for Metal Oxide Silicon Field Effect Transistor or Metal Oxide Semiconductor Field Effect Transistor.
(JFET) stands for junction gate field-effect transistor (JFET)
2. JFET is a three-terminal semiconductor device, whereas MOFET a four-terminal semiconductor device.
3. In terms of areas of application of JFETs are used in low noise applications while MOSFETs, are used for high noise applications
Answer:
Explanation:
First, we will find actual properties at given inlet and outlet states by the use of steam tables:
AT INLET:
At 4MPa and 350°C, from the superheated table:
h₁ = 3093.3 KJ/kg
s₁ = 6.5843 KJ/kg.K
AT OUTLET:
At P₂ = 125 KPa and steam is saturated in vapor state:
h₂ = 
= 2684.9 KJ/kg
Now, for the isentropic enthalpy, we have:
P₂ = 125 KPa and s₂ = s₁ = 6.5843 KJ/kg.K
Since s₂ is less than 
and greater than 
at 125 KPa. Therefore, the steam is in a saturated mixture state. So:
Now, we will find 
(enthalpy at the outlet for the isentropic process):
Now, the isentropic efficiency of the turbine can be given as follows:
Answer:
B- extreme fit, close fit, adjustable fit
Explanation:
A human-fit design typically involves the process of manufacturing or producing products (tools) that are easy to use by the end users. Therefore, human-fit designs mainly deals with creating ideas that makes the use of a particular product comfortable and convenient for the end users.
The design for human-fit strategies include; extreme fit, close fit and adjustable fit.
Hence, when the aforementioned strategies are properly integrated into a design process, it helps to ensure the ease of use of products and guarantees comfort for the end users.
