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Vadim26 [7]
4 years ago
6

Write using about 10-15 lines for each of the six materials (metals, ceramics, glasses, polymers, composites, and semiconductors

). For each, list at least three most important properties, two drawbacks, three well-known examples, and three well-known applications.
Engineering
1 answer:
Svetradugi [14.3K]4 years ago
8 0

Answer:

See Answer below- Explanation is the entire answer

Explanation:

Metals:

Properties: Ductile, good heat conductivity, good electrical conductivity, high strength;

Drawbacks: Relatively high weight, reactive with oxygen to create oxides- corrosion is presented;

Examples: steel, aluminum alloys, brass, copper, titanium

Applications: Body of the vehicles, structures in the skyscrapers, cooking pots.

Ceramics:

Properties: Brittle, poor heat conductors, poor electrical conductors, high wear resistance, corrosion resistance;

Drawbacks: Deforms by fracturing, shock resistance is low, no conductivity of electricity;

Examples: concrete, tungsten carbide, diamond

Applications: bricks for constructions, clay pots to keep heat, cutting tools for metals;

Glasses:

Properties: amorphous, transparent, high weight

Drawbacks: poor conductors of heat and electricity; brittle; low shock resistance;

Examples: Silica, lead glass, glaze;

Applications: windows, protection screens;

Polymers:

Properties: low density, recyclable, poor heat and electrical conductors, plastic deformation;

Drawbacks: low strength, low operating temperatures;

Examples: polyethylene, nylon, ABS-plastic, rubber;

Applications: toys, tires, insulation covers for the wires.

Composites:

Properties: high strength to weight ratio, can get combination of properties from the used materials, rarely conductive, good shock resistance;

Drawbacks: high cost, hard to recycle, expensive;

Examples: steel-reinforced concrete, carbon fiber, fiber glass, Nomex, sandwich roof panels;

Applications: buildings, bullet proof vests, body of the Formula 1 cars, rockets, roof panels.

Semiconductors:

Properties: brittle, change conductive behavior under certain scenario, poor heat conductors;

Drawbacks: hard to manufacture, expensive;

Examples: Silicon-based semiconductors, Germanium-based semiconductors, Ga-based semiconductors;

Applications: chips, LED, diodes, transistors, op-amps, microprocessors.

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the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg

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\delta \ T = \frac{-V (1- \beta \ T}{C_p} * \delta \ P ( \frac{1}{9.87} \ \frac{J}{cm^3/atm})\delta \ T = \frac{-1.001 \frac{cm^3}{gm} (1- 1.5*10^{-4} \  K^{-1} )*2}{4.19 \ \frac{J}{gm.K}} *(5-1)atm ( \frac{1}{9.87} \ \frac{J}{cm^3/atm})

Δ T = 0.093 K

Now; we can calculate the lost work bt the formula:

W_{lost} = T_{surr} *S

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T_{surr} is the temperature of the surrounding. = 20°C = (20+273.15)K =  293.15 K

From above the change in entropy is:

\delta \  S = C_p \  In (\frac{T+ \delta \ T }{T}) *  \beta V \delta P

\delta \  S = 4.19*  \  In (\frac{288.15+0.093 }{288.15}) -  1.5*10^{-4} * 1.001 (5-1)* (\frac{1}{9.87})

\delta \  S =1.408*10^{-3} \ J/gm.K

W_{lost} = T_{surr} *S

W_{lost} = 293.15* 1.408*10^{-3} \ J/gm.K

W_{lost} = 0.413 \  kJ/kg

Thus, the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg

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