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alexdok [17]
3 years ago
13

A 6.0x10-2kg hollow racquetball with an initial speed of 18.6 m/s collides with a backboard. It rebounds with a speed of 4.6 m/s

. Calculate the total impulse that the wall imparts on the ball on the ball.
Physics
1 answer:
trapecia [35]3 years ago
6 0

Answer:

The total impulse that the wall imparts on the ball on the ball is 1.392 kg-m/s.

Explanation:

Given that,

Mass of the racquetball, m=6\times 10^{-2}\ kg

Initial speed of the ball, u = 18.6 m/s

Final speed of the ball, v = -4.6 m/s (the ball rebounds so it will be negative)

We need to find the total impulse that the wall imparts on the ball on the ball. We know that the change in momentum of an object. It is given by :

J=m(v-u)

J=6\times 10^{-2}\times (-4.6-18.6)

J = -1.392 kg-m/s

So, the total impulse that the wall imparts on the ball on the ball is 1.392 kg-m/s. Hence, this is the required solution.

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Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
\frac{U_k}{U_0}= \frac{ \frac{1}{2}kC_0 V^2 }{ \frac{1}{2} C_0 V^2}=  k
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3 years ago
Dwight uses a spring (k = 70 N/m) on a horizontal surface to make a launcher for model cars. The spring is attached to a holder
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Part A)

As we know that spring force is given by

F = kx

here x = stretch in the spring from natural length

So here  when spring reaches to its natural length

Force due to spring = 0

so acceleration = 0

Part b)

When spring is compressed from its natural length it will have elastic potential energy in it

so it is given by

U = \frac{1}{2}kx^2

now we know that there is no friction in it so maximum kinetic energy of the launcher must be equal to the elastic potential energy of the spring

KE = \frac{1}{2}kx^2

here we have

k = 70 N/m

x = 0.4 m

KE = \frac{1}{2}(70)(0.4)^2

KE = 5.6 J

Part c)

Now to find the speed we know that

KE = \frac{1}{2} mv^2

5.6 = \frac{1}{2}0.3v^2

v = 6.11 m/s

so its speed is 6.11 m/s

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Answer:

t = 12s

Explanation:

Given:

v-initial = 0 m/s

x = 360 m

a = 5.0 m/s^2

Solve:

x = (v-initial)t + 1/2(a*t^2)

360 = 0t + 1/2 (5.0t^2)

360 = 2.5 t^2

144 = t^2

t = sqrt(144) = 12

Therefore, it takes 12 seconds.

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Answer:

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Carlos gives a grocery cart a 60-N push. The cart has a mass of 40 kg. What is the cart's acceleration?
andre [41]
<h3>Answer:</h3>

1.5 m/s²

<h3>Explanation:</h3>

We are given;

Force as 60 N

Mass of the Cart as 40 kg

We are required to calculate the acceleration of the cart.

  • From the newton's second law of motion, the rate of change in momentum is directly proportional to the resultant force.
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Rearranging the formula we can calculate acceleration, a

a = F ÷ m

  = 60 N ÷ 40 kg

  = 1.5 m/s²

Therefore, the acceleration of the cart is 1.5 m/s²

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