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Alekssandra [29.7K]
3 years ago
9

A packet weighs 40kg in air but when it is totally submerged into a 1mx1m square tank the weight of the packet is only 18kg. How

much does the water rise in the tank?
Engineering
1 answer:
Irina18 [472]3 years ago
5 0

Answer:

water  rise = 22 mm

Explanation:

weight of packet IN AIR = 40 *9.81 =392.4 N

weight of packet  IN WATER= 18 *9.81 =176.58 N

by Archimedi's principle

difference in weight = weight of displaced water

w_a - w_w = \rho_w v_d g

392.4 - 176.58 = 1000* v_d* 9.81

v_d = 0.022 m^3

v_d = A*H_rise

0.022 =1*H_rise

H_rise = 0.022 m = 22 mm

water  rise = 22 mm

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\theta_1=15^o\\\theta_2=75^o

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<u>Projectile Motion</u>

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\displaystyle \theta_1=\frac{asin\left(\frac{70\times 9.8}{37^2}\right)}{2}

\theta_1=15^o

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\theta_2=90^o-15^o=75^o

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