Answer:
0.36 M
Explanation:
Let's consider the following neutralization reaction.
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
25 mL of 0.83 M NaOH reacted. The moles of NaOH that reacted are:
0.025 L × 0.83 mol/L =0.021 mol
The molar ratio of NaOH to HCl is 1:1. The moles of HCl that reacted are 0.021 moles.
0.021 moles are contained in 58 mL of HCl. The molar concentration of HCl is:
M = 0.021 mol/0.058 L
M = 0.36 M
P 15 atm
V₁ = 12x103 m3 -3 3 V₁ = 12x10 m" T₁ = 25°c T= 28815 K
P₁ = 1.52x10 Pa
Now, Finel quantities, T₂ = 35°C = 308.15 °K
V2= 851 = -3 3
Now
by ideal gas equation
P2Y2 T2
= PV, T2
1152 X106 x 12x16 3 x 308115 8,5×103 x 288,15 = Pa
=
21294×10 Pa
P₂ = 21264 Atm
final
pressure will be
21264 Adm.
Please check the attached file for a brief answer.
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The moles of I₂ will form from the decomposition of 3.58g of NI₃ is 0.0136 moles.
<h3>How we calculate moles?</h3>
Moles of any substance will be calculated as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is:
2NI₃ → N₂ + 3I₂
Moles of 3.58g of NI₃ will be calculated as:
n = 3.58g / 394. 71 g/mol = 0.009 moles
From the stoichiometry of the solution, it is clear that:
2 moles of NI₃ = produce 3 moles of I₂
0.009 moles of NI₃ = produce 3/2×0.009=0.0136 moles of I₂
Hence, option (3) is correct i.e. 0.0136 moles.
To know more about moles, visit the below link:
brainly.com/question/15303663
I think the correct answer from the choices listed above is option 1. It would be the molecule carbon disulphide that will be polar, based on the structure of the choices given. Hope this answers the question. Have a nice day. Feel free to ask more questions.
