For the part a) we need only the momentum of the box and we have the data to find it.
Momentum is given by,
where clearly, p is the momentum, m the mass of the box and v is the velocity.
Substituting,
For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,
<em>It is the same that part a)</em>
Answer:
<em>1.49 x </em><em></em>
<em></em>
Explanation:
Kepler's third law states that <em>The square of the orbital period of a planet is directly proportional to the cube of its orbit.</em>
Mathematically, this can be stated as
∝
<em>to remove the proportionality sign we introduce a constant</em>
= k
k =
Where T is the orbital period,
and R is the orbit around the sun.
For mars,
T = 687 days
R = 2.279 x
for mars, constant k will be
k = = 3.987 x
For Earth, orbital period T is 365 days, therefore
= 3.987 x
x
= 3.34 x
R =<em> 1.49 x </em><em></em>