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GarryVolchara [31]
3 years ago
8

Solve for w. 16w − 18w − –7w + –11 = 19 (99 smartscore on IXL plz help)

Mathematics
1 answer:
sergey [27]3 years ago
6 0

Answer:

w = 6

Step-by-step explanation:

16w − 18w − –7w + - 11 = 19

5w+ -11 = 19

5w = 30

w = 6

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5x - 4y = -8<br> x + 4y = -16
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Answer:

(-4 , -3)

Step-by-step explanation:

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Write an equation of a line that is parallel to x=8 and that passes through the point (-3,-2)
alukav5142 [94]
The answer is 22 because you have 8 then you multiply 3 that gives you 24 then you subtract 2 and that. gives. you 22
3 0
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A trapezoid has an area of 97.2 square meters. One base is 10 meters long. The other base is 6.2 meters long. What is the height
Masja [62]

Answer:

126.20 meters.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Evaluate the sum of the following finite geometric series.
rjkz [21]

Answer:

\large\boxed{\dfrac{156}{125}\approx1.2}

Step-by-step explanation:

<h3>Method 1:</h3>

\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\\\\for\ n=1\\\\\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1\\\\for\ n=2\\\\\left(\dfrac{1}{5}\right)^{2-1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}\\\\for\ n=3\\\\\left(\dfrac{1}{5}\right)^{3-1}=\left(\dfrac{1}{5}\right)^2=\dfrac{1}{25}\\\\for\ n=4\\\\\left(\dfrac{1}{5}\right)^{4-1}=\left(\dfrac{1}{5}\right)^3=\dfrac{1}{125}

\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}=1+\dfrac{1}{5}+\dfrac{1}{25}+\dfrac{1}{125}=\dfrac{125}{125}+\dfrac{25}{125}+\dfrac{5}{125}+\dfrac{1}{125}=\dfrac{156}{125}

<h3>Method 2:</h3>

\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\to a_n=\left(\dfrac{1}{5}\right)^{n-1}\\\\\text{The formula of a sum of terms of a geometric series:}\\\\S_n=a_1\cdot\dfrac{1-r^n}{1-r}\\\\r-\text{common ratio}\to r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=\left(\dfrac{1}{5}\right)^{n+1-1}=\left(\dfrac{1}{5}\right)^n\\\\r=\dfrac{\left(\frac{1}{5}\right)^n}{\left(\frac{1}{5}\right)^{n-1}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\r=\left(\dfrac{1}{5}\right)^{n-(n-1)}=\left(\dfrac{1}{5}\right)^{n-n+1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}

a_1=\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1

\text{Substitute}\ a_1=1,\ n=4,\ r=\dfrac{1}{5}:\\\\S_4=1\cdot\dfrac{1-\left(\frac{1}{5}\right)^4}{1-\frac{1}{5}}=\dfrac{1-\frac{1}{625}}{\frac{4}{5}}=\dfrac{624}{625}\cdot\dfrac{5}{4}=\dfrac{156}{125}

5 0
3 years ago
How to round to the nearest thousandth
djyliett [7]

if the number we were rounding was 2.4784

Number to the right of the thousandth digit is 4.

Since 4 is less than 5 we round down and leave the

thousandth place digit unchanged.

Answer: 2.4780  

Remember: If less than 5, round down. If 5 or greater,  

round up.

Step-by-step explanation:

8 0
3 years ago
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