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3 years ago

Describe the chemicals used to treat the oil spill, and some of the limitations of using them.

Chemistry

1 answer:

Alex17521 [72]3 years ago

3 0

Answer:

Dispersants

Dispersants are generally detergents or surfactants that help dissolve the oil stain in smaller drops. They remove oil from the water surface, making it enter and into the water column, increasing the speed of biological degradation. These dispersants, by removing oil from the water surface, protect birds, marine mammals, turtles and sensitive coasts. Chemical dispersants do not sink oil leaving it suspended in the water column. Dispersants should be avoided in shallow coastal waters, mangroves, swamps, or waters over coral reefs and algae due to their possible toxicity.

Explanation:

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Un mol de Neón ocupa un volumen de 5 lt y una temperatura 300°K, cuál será su volumen si la temperatura disminuye en 50 °K, P y

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Answer:

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Explanation:

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2 years ago

If a measurement is recorded as 1.2 cm, what is the smallest marking on the instrument?

zhannawk [14.2K]

The smallest marking would be 1/10th of a centimeter

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2 years ago

A cell using protein-mediated facilitated diffusion is treated with a toxin that prevents conformation change in the membrane pr

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2 years ago

The empirical formula of a compound is CH. At 200 degree C, 0.145 g of this compound occupies 97.2 mL at a pressure of 0.74 atm.

Vladimir [108]

Answer:

The molecular formula = $C_{6}H_{6}$

Explanation:

Given that:

Mass of compound, m = 0.145 g

Temperature = 200 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (200 + 273.15) K = 473.15 K

V = 97.2 mL = 0.0972 L

Pressure = 0.74 atm

Considering,

$n=\frac{m}{M}$

Using ideal gas equation as:

$PV=\frac{m}{M}RT$

where,

P is the pressure

V is the volume

m is the mass of the gas

M is the molar mass of the gas

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the values in the above equation as:-

$0.74\times 0.0972=\frac{0.145}{M}\times 0.0821\times 473.15$

$M=78.31\ g/mol$

The empirical formula is = $CH$

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12 + 1 = 13 g/mol

Molar mass = 78.31 g/mol

So,

Molecular mass = n × Empirical mass

78.31 = n × 13

⇒ n ≅ 6

The molecular formula = $C_{6}H_{6}$

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3 years ago

Lines on a map joining places that have the same temperature?

vazorg [7]

Answer:

Isotherms

Explanation:

8 0

3 years ago

Read 2 more answers