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4 years ago

Describe the chemicals used to treat the oil spill, and some of the limitations of using them.

Chemistry

1 answer:

Alex17521 [72]4 years ago

3 0

Answer:

Dispersants

Dispersants are generally detergents or surfactants that help dissolve the oil stain in smaller drops. They remove oil from the water surface, making it enter and into the water column, increasing the speed of biological degradation. These dispersants, by removing oil from the water surface, protect birds, marine mammals, turtles and sensitive coasts. Chemical dispersants do not sink oil leaving it suspended in the water column. Dispersants should be avoided in shallow coastal waters, mangroves, swamps, or waters over coral reefs and algae due to their possible toxicity.

Explanation:

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O2- is the Lewis ______ in the following reaction

matrenka [14]

$O^{2-}$ is the Lewis base in the following reaction:

$SO_3(g) + O^{2-}(aq)$ → $SO_4^{2-}(aq)$

<h3>What is lewis base? </h3>

Lewis base is a species that donates an electron pair.

In the above-given chemical equation, the $O^{2-}$ is the lewis base which is donating an electron pair to the central atom of $SO_3$ to form $SO_4^{-2}$ .

Hence, $O^{2-}$ is the Lewis base in the following reaction:

$SO_3(g) + O^{2-}(aq)$ → $SO_4^{2-}(aq)$

Learn more about the lewis base here:

brainly.com/question/15570523

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3 0

2 years ago

A scientist measures the standard enthalpy change for the following reaction to be -17.2 kJ : Ca(OH)2(aq) 2 HCl(aq)CaCl2(s)

elixir [45]

Answer: $\Delta H^{0}=-173.72$ kJ/mol

Explanation: Enthalpy Change is the amount of energy in a reaction - absorption or release - at a constant pressure. So, Standard Enthalpy of Formation is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

$\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}$

$Ca(OH)_{2}_{(aq)}+2HCl_{(aq)}$ → $CaCl_{2}_{(s)}+2H_{2}O_{(l)}$

Standard Enthalpy of formation for the other compounds are:

Calcium Hydroxide: $\Delta H^{0}=$ -1002.82 kJ/mol

Calcium chloride: $\Delta H^{0}=$ -795.8 kJ/mol

Water: $\Delta H^{0}=$ -285.83 kJ/mol

Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

$-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H]$

$-17.2=-1367.46+1002.82-2\Delta H$

$2\Delta H=17.2-364.64$

$\Delta H=-173.72$

So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

8 0

3 years ago

The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime

krok68 [10]

Answer: The rate constant for the reaction is $3.96\times 10^{-3}min^{-1}$

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = $2.83\times 10^{-3}$

a - x = amount left after decay process = $3.06\times 10^{-4}$

$559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}$

$k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}$

$k=3.96\times 10^{-3}min^{-1}$

The rate constant for the reaction is $3.96\times 10^{-3}min^{-1}$

6 0

3 years ago

What is Gay lussac's law

k0ka [10]

Explanation:

Gay-Lussac's law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas when the volume is kept constant. Mathematically, it can be written as: {\displaystyle {\frac {P}{T}}=k}. It is a special case of the ideal gas law.

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3 years ago

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blondinia [14]

Answer:

Chemical nomenclature

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3 years ago