It means that velocity not only has a size, but it also has a direction.
Some other vector quantities are force and acceleration.
They have sizes and directions.
Temperature, cost, and weight are quantities with only size and no direction.
Those are called "scalar" quantities.
Answer:
the tension is 18513N
Explanation:
Given that
mass = 1683kg
acceleration = 1.2m/s^2
acceleration due to gravity = 9.8m/s^2
T-mg = ma
T = ma + mg
T = m(a +g)
T = 1683 kg(1.20 m/s2 + 9.8)
T = 1683 (11)
T = 18513N
therefore, the tension is 18513N
Answer:
<h2>
The answer is </h2><h2>
a. 5g/mL</h2>
Explanation:
Given data
mass m= 45g
volume v= 9mL
we know that density=m/v
substituting our given data we have

What is Density?
The Density of a body can be defined as the ratio of mass to volume,
or
Density, mass of a unit volume of a material substance. The formula for density is
,
where d is density,
M is mass, and
V is volume.
Density is commonly expressed in units of grams per cubic centimetre.
The horizontal components, being opposite in direction, will produce a shearing effect on the tendon, leading to injury. Thus, they will be added.
As the angle of 23 is from the vertical, we calculate the horizontal component by using
Weight acting * sin(23)
And multiply it by 2 to get the total shearing force
The weight acting is 12 times their body weight. Thus:
53 * 9.81 * 12 = 6239.2 Newtons
The total force acting on the tendon:
2 * sin(23) * 6239.2
= 4,880
= 4,900 Newtons (2 significant figures)
The charge accumulated in 3.25 μF capacitor is 178.75 μC.
Answer:
Explanation:
In parallel connection, the voltage drop across any passive devices like capacitor or resistor will be constant. So the current flow will be varying in case of parallel connections of capacitors or resistors.
As the capacitance is the measure of amount of charge or current generated for a given amount of voltage, it is directly proportional to the charge or current and inversely proportional to voltage.
C = Q/V
Here the charge accumulated in a capacitor of capacitance 3.25 microfarad need to be determined which is in parallel connection with another capacitor. So the voltage through both the capacitor will be equal to the voltage of the battery which is stated as 55 V.
3.25×
= Q/55
Q = 3.25 * 55 = 178.75 μC
So the charge accumulated in 3.25 μF capacitor is 178.75 μC.