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3 years ago

If a ship is moving forward has positive acceleration what can be said about the velocity of the ship?

Physics

1 answer:

ra1l [238]3 years ago

7 0

Increasing

Explanation:

If a ship is moving forward and has a positive acceleration, we can say that the velocity of the ship is increasing.

Velocity is the rate of change of displacement of a body with time.

Acceleration is the rate of change of velocity with time.

Acceleration = $\frac{change in velocity }{time}$

If a ship is moving with positive acceleration, the velocity of the ship is increasing also.

This is because when velocity is increasing, the change will be positive.
From the equation, to have positive velocity, the final velocity must be greater than the initial one.
With this, acceleration will be positive.
So we can say, velocity of the ship is increasing.

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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Approximately 101 N air is in a column 1-cm2 in cross-section that extends from sea level to the top of the atmosphere

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2 years ago

As you know, the oceans are a complex system that covers most of the earth, and contains a huge amount of resources. Protecting

Lana71 [14]

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2 years ago

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Oil having a density of 926 kg/m3 floats on water. A rectangular block of wood 3.69 cm high and with a density of 974 kg/m3 floa

zloy xaker [14]

Answer:

the position of the wood below the interface of the two liquids is 2.39 cm.

Explanation:

Given;

density of oil, $\rho _o$ = 926 kg/m³

density of the wood, $\rho _{wood}$ = 974 kg/m³

density of water, $\rho _w$ = 1000 kg/m³

height of the wood, h = 3.69 cm

Based on the density of the wood, it will position across the two liquids.

let the position of the wood below the interface of the two liquids = x

Let the wood be in equilibrium position;

$F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood} -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood} -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm$

Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.

6 0

3 years ago

An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis.

zhenek [66]

Answer:

2 m/s and -2 m/s

Explanation:

The object travels with an angle of

60.0°

with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).

If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:

$v_x = v cos \theta = (4.0 m/s) cos 60.0^{\circ}=2 m/s$

If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:

$v_x = -v cos \theta = -(4.0 m/s) cos 60.0^{\circ}=-2 m/s$

5 0

3 years ago

In a city grid, each block on the east-west streets is 100 meters long. Each block on the north-south streets is 20 meters long.

alex41 [277]

Answer:

72.1 m

Explanation:

Hello!

When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.

Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.

Since the directions west and south are perpendicular, the distance between the start ad end point is:

d = √(400^2 + 80^2) m = 407.92 m

However the walker traveled 480 m

Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance

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3 years ago