Answer:
Rowan's feet appears at a distance of 0.451 m under water
Solution:
As per the question:
Actual depth in water, d = 0.60 m
Normal distance of her feet from her eyes, D = 1.60 m
Now,
We know that refractive index of water, 
Thus
To calculate the apparent height of her feet:


To solve this question we will use ideal gas equation:

Where:
p = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
We can rearrange formula to get:

We are working woth same gas so we can write following formula. Index 1 stands for conditions before change and index 2 stands for conditions after change.

We are given:
p1=92.1kPa = 92100Pa
V1=200mL = 0.2L
T1=275K
p2= 101325Pa
T2=273K
V2=?
We start by rearranging formula for V2. After that we can insert numbers:
Answer:
the frequency of the hummingbird is 80 Hz.
Explanation:
Given;
number of times the hummingbird beats its wings, n = 4,800 times
the duration of this motion, t = 1 minute
The frequency of the hummingbird wings is calculated as follows;

Therefore, the frequency of the hummingbird is 80 Hz.
Answer:
1.1 lbs
Explanation:
To convert kg to lbs you multiply kilograms by 2.2. So 0.5kg × 2.2 equals to 1.1 lbs