Read the intro to lab 10. We are going to assume that the experiment was done in a styrofoam cup, so we are not going to include
1 answer:
Answer:
e% = 3.4%
Explanation:
This is a calorimetry problem where the heat released equals the heat absorbed
m (T₀ - T_f) = M c_{e2} (T₁ - T_f)
Index 1 refers to water and index 2 to metal, in this case it asks for the specific heat of the metal (c_{e2})
c_{e2} = m / M c_{e1} (T_f -T₀) / (T₁ - T_f)
Let's calculate
c_{e} = 60/100 4.19 (24-20) / (100-24)
c_{e2} = 0.1323 j / gC
This metal is possibly lead, which is its specific heat is 0.128 J / gC
The percentage error is
e% = (c_{e2} - 0.128) /0.128 100
e% = 3.4%
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The magnetic force on a current-carrying wire due to a magnetic field is given by
where
I is the current
L the wire length
B the magnetic field strength
In our problem, L=1.0 m,
and 
, so we can re-arrange the formula to find the current in the wire:
where
I is the current
L the wire length
B the magnetic field strength
In our problem, L=1.0 m,
Answer:
The specific heat capacity is q_{L}=126.12kJ/kg
The efficiency of the temperature is n_{TH}=0.67
Explanation:
The p-v diagram illustration is in the attachment
T_{H} means high temperature
T_{L} means low temperature
The energy equation :
= R*
in(
/
)
The specific heat capacity:
=q_{h}*(T_{L}/T_{H})
q_{L}=378.36 * (400/1200)
q_{L}=378.36 * 0.333
q_{L}=126.12kJ/kg
The efficiency of the temperature will be:
=1 - (
/
)
n_{TH}=1-(400/1200)
n_{TH}=1-0.333
n_{TH}=0.67
For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle is mathematically given as
theta=25.3
Option A is correct
<h3> What angle does the 18th minimum occur?</h3>Generally, the equation for the the angle is mathematically given as
Therefore
In conclusion
theta/7=16/5
theta=10*7/5
theta=25.3
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