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Reil [10]
3 years ago
5

What happens to the amplitude of the resultant wave when two sound waves with equal amplitude constructively interfere?

Physics
2 answers:
Darina [25.2K]3 years ago
7 0
Constructive interference means that the waves combine instead of negate. if they are both amplitude x, adding them together would result in 2x, or doubling the amplitude of one of the waves
Alinara [238K]3 years ago
4 0

Answer:

The amplitude of the resultant wave will be twice the amplitude of each wave

Explanation:

- Constructive interference occurs when two waves meet in phase (\theta=0^{\circ}, which means that the crest of a wave meets the crest of the other wave: in this case, the amplitude of the resultant wave is the sum of the amplitudes of the single waves

- Destructive interference occurs when the two waves meet in anti-phase (\theta=180^{\circ}, which means that the crest of a wave meets the trough of the other wave: in this case, the amplitude of the resultant wave is the difference between the amplitudes of the single wave

In this problem, we have constructive interference between the two waves: this means that the resultant amplitude is the sum of the two waves. Since the two waves have equal amplitude (we can call it A), the resultant amplitude will be

R= A+A=2 A

so, twice the amplitude of the single wave.


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A solar collector is a device that absorbs ___________from the sun ?
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SUNLIGHT OR SUNRAYS OR ENERGY OR HEAT

Explanation:

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A bakery measured the mass of a whole cake as 0.870 kg. A customer bought one slice of the cake and measured the mass of the sli
Brrunno [24]

Answer:

0.7549kg

Explanation:

The mass of the slice + mass of the remaining cake = total mass of cake.

mass of remaining cake = total mass of cake - the mass of the slice

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6 0
3 years ago
Lasers are now used in eye surgery. Given the wavelength of a certain laser is 514 nm and the power of the laser is 1.1 W, how m
Leno4ka [110]

Answer: 1.593*10^{17} photons released if the laser is used 0.056 s during the surgery

                           

Explanation:

First, you have to calculate the energy of each photon according to Einstein's theoty, given by:

                            E =\frac{hc}{\lambda}

Where \lambda is the wavelength, h is the Planck's constant and  h is the speed of light

              h = 6.626*10^{-34} \frac{m^{2} kg }{s}  -> Planck's constant

              c = 3*10^{8} \frac{m}{s}  -> Speed of light

So, replacing in the equation:

                E =\frac{ 6.626*10^{-34} \frac{m^{2} kg }{s}*3*10^{8} \frac{m}{s}}{514*10^-9 m}

Then, the energy of each released photon by the laser is:

                E = 3.867*10^{-19} \frac{J}{photons}

After, you do the inverse of the energy per phothon and as a result, you will have the number of photons in a Joule of energy:

               \frac{1}{3.867*10^{-19}} = 2.586*10^{18} \frac{photons}{J}

The power of the laser is 1.1 W, or 1.1 J/s, that means that you can calculate how many photons the laser realease every second:

              2.586*10^{18}\frac{photons}{J} * 1.1 \frac{J}{s} = 2.844*10^{18} \frac{photons}{s}

And by doing a simple rule of three, if 2.844*10^{18} photons are released every second, then in 0.056 s:

            0.056 s*2.844*10^{18} \frac{photons}{s} = 1.593*10^{17} photons are released during the surgery

5 0
3 years ago
A piano emits frequencies the range from a low of about 28 Hz to a high of about 4200 Hz. Find the range of wavelengths in air a
Step2247 [10]
V=wave velocity , <span>f= frequency, </span><span>λ=wavelength </span>
<span>Use it to find corresponding wavelengths for</span><span> f=28 Hz </span>
<span>λ= v/f= 337/28=12.036 m 
</span>
<span>for f=4200 Hz </span>
<span>λ= v/f=337/4200= 0.08 m </span>
<span>So max. wavelength is 12.036 m and </span>
<span>Min Wavelength is 0.08 m </span>
<span>So the range is between .08 m and 12.036 m
</span>Hope this helps. 
4 0
3 years ago
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