Answer:
42.50 dB
Explanation:
Determine the minimum voltage gain
amplitude of input signal ( Vi ) = 15 mV
amplitude of output signal ( Vo) = 2 V
Vo = 2 v
therefore ; minimum gain = Vo / Vi = 2 / ( 15 * 10^-3 )
= 133.33
Minimum gain in DB = 20 log ( 133.33 )
= 42.498 ≈ 42.50 dB
GPS device details are given below.
Explanation:
Even a simple GPS unit has a wide range of settings and features. Because every unit’s operation varies, this article won’t provide step-by-step details. Read the owner's manual to familiarize yourself with it..
If you’d like additional help, you can also sign up for a GPS navigation class at an REI store.
Though steps vary, all GPS receivers do the following basic functions:
Display position: A GPS tells you where you are by displaying your coordinates; it also shows your position on its base map or topo map.
Record tracks: When tracking is turned on, a GPS automatically lays down digital bread crumbs, called “track points,” at regular intervals. You use those later to retrace your steps or to evaluate the path you traveled.
Navigate point-to-point: A GPS directs you by giving you the direction and distance to a location, or “waypoint.” You can pre-mark waypoints by entering their coordinates at home. In the field you can have the unit mark a waypoint at a place you'd like to return to, such as the trailhead or your campsite. A GPS unit provides the bearing and distance “as the crow flies” to a waypoint. Because trails don’t follow a straight line, the bearing changes as you hike. The distance to travel also changes (decreasing, unless you’re heading the wrong direction) as you approach your goal.
Display trip data: This odometer-like function tells you cumulative stats like how far you’ve come and how high you’ve climbed.
GPS and your computer: GPS units come with a powerful software program that lets you manage maps, plan routes, analyze trips and more. Invest the time to learn it and to practice using all of its capabilities.
Answer:
The inductance of the inductor is 0.051H
Explanation:
From Ohm's law;
V = IR .................. 1
The inductor has its internal resistance referred to as the inductive reactance, X
, which is the resistance to the flow of current through the inductor.
From equation 1;
V = IX
X = 
................ 2
Given that; V = 240V, f = 50Hz, 
= 
, I = 15A, so that;
From equation 2,
X= 
= 16Ω
To determine the inductance of the inductor,
X = 2fL
L = 
= 
= 0.05091
The inductance of the inductor is 0.051H.
Answer:
radius = 0.045 m
Explanation:
Given data:
density of oil = 780 kg/m^3
velocity = 20 m/s
height = 25 m
Total energy is = 57.5 kW
we have now
E = kinetic energy+ potential energy + flow work
![E = \dot m ( \frac{v^2}{2] + zg + p\nu)](https://tex.z-dn.net/?f=E%20%3D%20%5Cdot%20m%20%28%20%5Cfrac%7Bv%5E2%7D%7B2%5D%20%2B%20%20zg%20%2B%20p%5Cnu%29)
![E = \dot m( \frac{v^2}{2] + zg + p_{atm} \frac{1}{\rho})](https://tex.z-dn.net/?f=E%20%3D%20%5Cdot%20m%28%20%5Cfrac%7Bv%5E2%7D%7B2%5D%20%2B%20%20zg%20%2B%20p_%7Batm%7D%20%5Cfrac%7B1%7D%7B%5Crho%7D%29)
solving for flow rate
![\dot m = 99.977we know that [tex]\dot m = \rho AV](https://tex.z-dn.net/?f=%5Cdot%20m%20%3D%2099.977%3C%2Fp%3E%3Cp%3Ewe%20know%20that%20%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cdot%20m%20%20%3D%20%5Crho%20AV)
solving for d
d = 0.090 m
so radius = 0.045 m
Answer should be B.3 hopefully
