"Acceleration" is any change in speed or direction of motion ...
slowing down, speeding up, or curving away from a straight line.
You and I, and all other students of Physics, must re-educate
people. We have to tell everyone that 'acceleration' does NOT
mean 'speeding up'. AND, it doesn't even necessarily mean
any change in speed.
Isı hangi faktöre bağlıdır?
Answer:
The answer to your question is: D.
Explanation:
Distance refers to the amount of space between two points, it is a scalar quantity.
Displacement refers to the space between two points, measure from the minimum path linking them, it is a vector quantity.
I'm not agree with these answers, because the total distance is approximately 500km.
A) The distance traveled is 300 km. This answer is not correct.
B) Distance is 300 km and displacement is 0 km. This answer is not correct because the displacement is also 500 km.
C) Distance is 300 km/hour and displacement is 300 km.
300 km/h is a measure of speed not of distance, this option is wrong.
D) Both distance traveled and displacement are 300 km. I think this is the correct answer because distance and displacement measure the same. but I think both measure 500 km.
Answer:
Consider the followig calculation
Explanation:
a) use deal equation:
PV = nRT
ρ = m/V,= ==> V = m/ρ
therefore,
ρ = Pm/RT
convert 95 oF in degree
95 oF = 308.15 K
1 atm = 1.013 * 105 pascal
ρ = 1.013*105 * 29 * /8.314 * 308.15
= 1.146 kg/m3
b) again use ideal gas equation:
ρ = Pm/RT
T = 50 oF = 283.15 K
1 atm = 1.013 * 105 pascal
molar mass will be same
ρ = 1.013 * 105 * 29 / 8.314 * 283.15
ρ = 1.248 kg / m3
So,
c) . more than density of the hot, dry air computed in part (a)
The final temperature of the mixture is closest to 32.5 °C
<h3>Data obtained from the question</h3>
- Mass of warm water (Mᵥᵥ) = 50 g
- Temperature warm water (Tᵥᵥ) = 40 °C
- Mass of cold water (M꜀) = 30 g
- Temperature of cold water (T꜀) = 20 °C
- Specific heat capacity of the water = 4.184 J/gºC
- Equilibrium temperature (Tₑ) =?
<h3>How to determine the equilibrium temperature </h3>
Heat loss = Heat gain
MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – M꜀)
50 × 4.184 (40 – Tₑ) = 30 × 4.184(Tₑ – 20)
209.2(40 – Tₑ) = 125.52(Tₑ – 20)
Clear bracket
8368 – 209.2Tₑ = 125.52Tₑ – 2510.4
Collect like terms
8368 + 2510.4 = 125.52Tₑ + 209.2Tₑ
10878.4 = 334.72Tₑ
Divide both side by 334.72
Tₑ = 10878.4 / 334.72
Tₑ = 32.5 °C
Learn more about heat transfer:
brainly.com/question/6363778
