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Anika [276]
4 years ago
10

He moves his sandpaper back and forth 45 times over a rusty area, each time moving a total distance of 0.15 m. Kevin pushes the

sandpaper against the surface with a normal force of 1.8 N. The coefficient of friction for the metal/sandpaper interface is 0.92. How much work is done by the kinetic frictional force during the sanding process
Physics
1 answer:
steposvetlana [31]4 years ago
3 0

Answer:

W = -11.178 J

Explanation:

In this question, Work is defined by the equation:

W = F•dx•cos(θ)

Where;

F is force

x is distance over which the force acts on the object,

θ = angle between force and direction of travel.

Now, because the force is constant in this case, we don't need make the equation an integral expression. Also, since the force of friction is always precisely opposite the direction of travel (i.e θ = 180°), the equation can be rewritten like this:

W = F•x•cos(180)

W = -F•x

The force of friction will be given by the equation:

F_fric = F_norm × coefficient of friction

Also, the total work will be the sum of all 45 passes by the sandpaper. Therefore, our final equation, when F_fric is substituted into the work equation, is:

W = -(45)×(F_norm)×(coeff of friction)×(distance)

We are given;

normal force = 1.8 N

Coefficient of friction for the metal/sandpaper interface = 0.92

Distance = 0.15 m

W = -(45) × (1.8) × (0.92) × (0.15)

W = -11.178 J

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Light striking a mirror at a 50° angle will be reflected at an angle _____.
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Hooke's law describes a certain light spring of unstretched length 34.8 cm. When one end is attached to the top of a doorframe a
DaniilM [7]

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a) k = 1343.6\,\frac{N}{m}, b) l = 0.501\,m\,(50.1\,cm)

Explanation:

a) The Hooke's law states that spring force is directly proportional to change in length. That is to say:

F \propto \Delta l

In this case, the force is equal to the weight of the object:

F = m\cdot g

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F = 80.614\,N

The spring constant is:

k = \frac{F}{\Delta l}

k = \frac{80.614\,N}{0.408\,m-0.348\,m}

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b) The length of the spring is:

F = k\cdot (l-l_{o})

l = l_{o} + \frac{F}{k}

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6 0
3 years ago
The maximum pressure most organisms can survive is about 1000 times the atmospheric pressure. Only small, simple organisms such
Schach [20]

Answer:

h = 10000 m

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The pressure applied at a depth of the liquid is given by:

P =ρgh

where,

P = Maximum Pressure to Survive = (1000)(Atmospheric Pressure)

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g = 9.8 m/s²

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1.01 x 10⁸ Pa = (1025 kg/m³)(9.8 m/s²)h

h = (1.01 x 10⁸ Pa)/(1025 kg/m³)(9.8 m/s²)

<u>h = 10000 m</u>

6 0
3 years ago
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