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2 years ago

8

The color of the explosive mixture is yellow, green, and red-orange. Explain how the colors are formed and which three metals we

re most likely present in the rocket??

1 answer:

Inessa [10]2 years ago

5 0

Answer:

m

Explanation:

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Alex cut a pizza into 8 equal slices. He removed 2 of the slices of pizza. What is the measure of the angle made by the missing

Firlakuza [10]

Answer: 90 degrees.

Explanation:

4 0

3 years ago

How do the differences in the polyatomic ions po3 3- and po4 3- help you determine whether each ends in -ite or -ate?

Tcecarenko [31]

There is a rule in naming polyatomic anions containing oxygen. Those names ending in <em>–ate</em> are given to the most common oxyanion of an element. While those names ending in <em>–ite</em> are for those that contains fewer O atom for the same charge. Since P $PO_{3} ^{3-}$ has fewer O atoms, its name ends in <em>–ite</em>. Thus, P $PO_{3} ^{3-}$ is phosphite while P $PO_{4} ^{3-}$ is phosphate.

4 0

3 years ago

What is the percent composition by mass of oxygen in Ca(NO3)2 (gram-formula= 164 g/mol)?

Neko [114]

To find this, we will use this formula:

Molar mass of element
------------------------------------ x 100
Molar mass of compound

So, first lets calculate the mass of the compound as a whole. We use the atomic masses on the periodic table to determine this.

Ca: 40.078 g/mol
N2 (there is two nitrogens): 28.014 g/mol
O6 (there are six nitrogens: 3 times 2): 95.994 g/mol

When we add all of those numbers up together, we get 164.086. That is the molar mass for the whole compound. However, we are trying to figure out what percent of the compound oxygen makes up. From the molar mass, we know that 95.994 of the 164.086 is oxygen. Lets plug those numbers into our equation!

95.994
-----------
164.086

When we divide those two numbers, we get .585. When we multiply that by 100, we get 58.5.

So, the percent compostition of oxygen in Ca(NO3)2, or, calcium nitrate, is 58.5%.

5 0

3 years ago

How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant

schepotkina [342]

Answer:

1.8 × 10² s

Explanation:

Let's consider the reduction that occurs upon the electroplating of copper.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We will establish the following relationships:

1 g = 1,000 mg
The molar mass of Cu is 63.55 g/mol
When 1 mole of Cu is deposited, 2 moles of electrons circulate.
The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
1 A = 1 C/s

The time that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

$336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s$

3 0

3 years ago

Matter and energy may be created or destroyed in a chemical reaction.

gulaghasi [49]

Answer:false

Explanation:matter cannot be created or destroyed in a chemical reaction it is rearranged

3 0

3 years ago