A 35.2-g sample of an alloy at 93.0°C is placed into 219 g of water at 22.0°C in an insulated coffee cup. Assume that no heat is absorbed by the cup. If the final temperature of the system is 31.1°C, what is the specific heat capacity of the alloy in J/(g.K)? Don't include units. cH2O = 4.184 J/g.K
1 answer:
Answer:
Explanation:
mass of the alloy = 35.2 g
temperature t of the alloy = 93° C
heat loss by alloy = mc ( t₁ - t₂) where t₁ = 93 and t₂ = 31.1° C
heat loss by alloy = 2178.88 c where c is the specific heat capacity of the alloy
heat gained by water = m cw ( t₂ - t₁ ) where t₁ of water = 22° C and t₂ of water = 31.1° C
heat gained by water = 8338.294
heat gained = heat loss
2171.84 c = 8338.294
c specific heat capacity of the alloy = 8338.294 / 2178.88 = 3.83 J/g.K
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