A) Work energy relation;
Work =ΔKE ; work done = Force × distance, while, Kinetic energy = 1/2 MV²
F.s = 1/2mv²
F× 4×10^-2 = 1/2 × 5 ×10^-3 × (600)²
F = 900/0.04
= 22500 N
Therefore, force is 22500 N
b) From newton's second law of motion;
F = Ma
Thus; a = F/m
= 22500/(5×10^-3)
= 4,500,000 m/s²
But v = u-at
0 = 600- 4500,000 t
t = 1.33 × 10^-4 seconds
120 acceleration oh yeah i am sure about this
Answer:
2100 J
Explanation:
The heat required to increase the temperature of a substance is given by

where
m is the mass of the substance
C is its specific heat capacity
is its change in temperature
For the water in this problem, we have:
m = 100 g is its mass
C = 4.2 J/g • °C is the specific heat capacity
is the increase in temperature
So, the amount of heat needed is:
