1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_lady [41]
2 years ago
7

Describe how the smoke particles move when a candle was blown out?​

Physics
1 answer:
lukranit [14]2 years ago
4 0

Answer:

When a candle was blown out, the flame stops immediately but the wick and the wax are both still hot, so pyrolysis continues for a few seconds. Explanation:

You might be interested in
Will Give Brainlist <br> Check pic for question
Harrizon [31]
Ohms law = v= Ir

V= 0.02 x 4000 = 80v
5 0
3 years ago
Read 2 more answers
Any object that has mass and takes up space is considered
sashaice [31]
Matter. I don't really know how to explain it. Sorry. But anyways, Hope this helps!
7 0
3 years ago
Compare animal and plant cell
vagabundo [1.1K]

Answer:

A plant cell contains a large, singular vacuole that is used for storage and maintaining the shape of the cell. In contrast, animal cells have many, smaller vacuoles. Plant cells have a cell wall, as well as a cell membrane. Animal cells simply have a cell membrane, but no cell wall.

hope this helps :)

8 0
2 years ago
Read 2 more answers
Who water rocket starts from rest and roses straight up with an acceleration of 5 m/s until it runs out of water 2.5 seconds lat
Kitty [74]

Answer:

23. 4375 m

Explanation:

There are two parts of the rocket's motion

1 ) accelerating  (assume it goes upto  h1 height )

using motion equations upwards

s = ut+\frac{1}{2}*a*t^{2} \\h_1=0+\frac{1}{2}*5*2.5^{2} \\=15.625 m

Lets find the velocity after 2.5 seconds (V1)

V = U +at

V1 = 0 +5*2.5 = 12.5 m/s  

2) motion under gravity (assume it goes upto  h2 height )

now there no acceleration from the rocket. it is now subjected to the gravity

using motion equations upwards (assuming g= 10m/s² downwards)

V²= U² +2as

0 = 12.5²+2*(-10)*h2

h2 = 7.8125 m

maximum height = h1 + h2

                            = 15.625 + 7.8125

                            = 23. 4375 m

3 0
3 years ago
A sled of mass 2.12 kg has an initial speed of 5.49 m/s across a horizontal surface. The coefficient of kinetic friction between
Darya [45]

Answer:

The speed of the sled is 3.56 m/s

Explanation:

Given that,

Mass = 2.12 kg

Initial speed = 5.49 m/s

Coefficient of kinetic friction = 0.229

Distance = 3.89 m

We need to calculate the acceleration of sled

Using formula of acceleration

a = \dfrac{F}{m}

Where, F = frictional force

m = mass

Put the value into the formula

a=\dfrac{\mu mg}{m}

a=\mu g

a=0.229\times9.8

a=2.244\ m/s^2

We need to calculate the speed of the sled

Using equation of motion

v^2=u^2-2as

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value in the equation

v ^2=(5.49)^2-2\times2.244\times3.89

v=\sqrt{(5.49)^2-2\times2.244\times3.89}

v=3.56\ m/s

Hence, The speed of the sled is 3.56 m/s.

8 0
3 years ago
Other questions:
  • Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to t
    10·1 answer
  • A hockey player makes a slap shot exerting a constant force of 40.0 newtons on the puck for .2 seconds. What is the magnitude of
    10·1 answer
  • A capacitor is connected to a power source and begins charging. What causes the capacitor to stop charging while it is still con
    10·1 answer
  • Is nickel coin magnetic?
    12·2 answers
  • Two objects of different mass rest on Earth. Which one experiences the greater acceleration due to gravity ?
    5·1 answer
  • All of the following objects are moving at the same speed. which one bas the greatest kinetic energy? (remember kinetic energy d
    8·1 answer
  • A What quantity is equal to​
    13·1 answer
  • An object undergoing simple harmonic motion completes one cycle of motion in 1.7 seconds. Determine the angular frequency (rad/s
    10·1 answer
  • A 25.0kg girl pushes a 50.0kg boy so that he accelerates at 4.00m/s2. What is the force of the boy on the girl? A. 200N B. 100N
    10·1 answer
  • State the factor that affect the gravitational force<br>​
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!