Answer: I2 is the Oxidant; while the 2S2O3(-2) is the reductant.
Explanation:
An Oxidant is any substance that oxidizes, or receives electrons from, another; in so doing, it becomes reduced in oxidation number.
A Reductant thus exactly the opposite.
Note that the equation provided shows that Iodine (I2) received an electron to become NEGATIVELY CHARGED:
I2 --> 2I-.
The oxidation number reduced from 0 to -1.
In contrast, the oxidation number of 2S2O3(-2) increases from -4 to -2.
Thus, I2 is the Oxidant; while the 2S2O3(-2) is the reductant.
The solubility is the guide to the maximum amount of solute that can be dissolved in a certain amount of solvent at a certain temperature to make a saturated solution. Any amount less than this would result to unsaturated, while any amount more would result to saturated.
6 g/(50 mL * 1 L/1000 mL) = 120 g/L
Since it is less than the solubility of 125 g/L, then <em>this solution is unsaturated</em>.
A) a column
example: earth alkaline metals
Answer:
6,613 M
Explanation:
Dilution is the process of reducing the concentration of a solute in solution, mixing initial solution with more solvent.
The concentration of Solution B is:
23,881 M × = 9,552 M
Because the initial eight parts are diluted to 12+8 parts.
Thus, concentration of solution C is:
9,552 M × = 6,613 M
I hope it helps!
The 2nd one I believe
Answer- 2nd
