Answer:
τ=0.060 N.m
Explanation:
By kinematics:
Solving for α:
where ωo = 600*2*π/60; ωf = 0; t=10s
The sum of torque is:
Some of the energy the car gained as it was pulled was lost because of heat from friction. The rest of the energy was transforme
d into potential energy. How much potential energy does the roller coaster car have at the top of the first hill? Use PE = m × g × h, and assume that g = 9.8 m/sec2.
2 answers:
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