Given :
Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .
To Find :
How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .
Solution :
By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.
So , volume of solution does not matter .
Moles of oxygen , 
.
Now , molecule of CO contains 1 mole of C .
So , moles of C is also 0.167 mole .
Mass of carbon , 
.
Therefore , mass of carbon is 2 grams .
Hence , this is the required solution .
Explanation:
example is copper iron...........
Answer:
Ryobi P517 18V Lithium Ion Cordless Brushless 2,900 SPM Reciprocating Saw w/ Anti-Vibration Handle and Tool-Less Blade Changing
Explanation:
Answer:
Z in chemistry means atomic number but I guess there is 'Zahl'
Answer:
4 sig figs
Explanation:
There are 4 because they are all # 1 or above.
0 has special rules on whether or not it is significant.
0 being between two other sig figs no matter how far apart makes it a sig fig.
example: 101 is 3 sig figs
0 that is at the end of a non decimal number are not significant.
example: 110 is 2 sig figs
0 that are after a decimal are significant as long as they after another sig fig.
example: 1.000 and .1000 are both 4 sig figs
extra examples:
110.01 is 5 sig figs
110.1 is 4 sig figs
.0001 is 1 sig figs
