The fringes will be farther apart
The width of the centre maxima on a screen is twice the distance between the dark fringes on either side at a distance L away: The pattern of light spreads out as you get further away from the screen (bigger L). The pattern of light widens as the hole gets smaller (smaller a).
<h3>What is Double slit experiment ?</h3>
The double-slit experiment involves directing a beam of light at a wall that has two vertical slits. The pattern that results from the light passing through the slits is captured on a photographic plate. A single line of light is seen when one slit is covered, aligned with the open slit.
- In essence, waves passing through two closely spaced, parallel slits produce an interference pattern on a screen. Everyone should know this. This is true for all types of waves sound wave, light wave etc
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The speed after 21 s is 18.9 m/s and the total time required for the train to reach a speed of 34 m/s is 14.4 s
<h3>
What is Speed ?</h3>
Speed is a distance travelled by a body per time taken. It is a scalar quantity and it is measured in m/s
Given that at Initially stationary, a train has a constant acceleration of 0.9 m/s2.
(a) What is its speed after 21 s?
- Acceleration a = 0.9 m/s²
Using v = u + at
Substitute all the parameters into the equation
v = 0 + 0.9 x 21
v = 18.9 m/s
(b) What is the total time required for the train to reach a speed of 34 m/s?
Let first calculate for total distance by using
v² = u² + 2as
34² = 18.9² + 2 × 0.9 × S
1156 = 357.21 + 1.8S
1.8S = 1156 - 357.21
1.8S = 798.79
S = 798.79 / 1.8
S = 443.8 m/s
v = u + at
34 = 21 + 0.9t
0.9t = 34 - 21
0.9t = 13
t = 13/0.9
t = 14.44s
Therefore, its speed after 21 s is 18.9 m/s and the total time required for the train to reach a speed of 34 m/s is 14.4 s
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<span>a. less biomass
b. more biomass
c. more broad-leaf trees
d. locations near the equator
i would say c
</span>
Answer:
Explanation:
mass of displaced oil = 11 x .9
= 9.9 gm
9.9 x 10⁻³ kg
weight of displaced oil = 9.9 x 9.81 x 10⁻³ N
= .097 N .
buoyant force by oil = .097 N
weight of unknown metal = .1 x 9.8
= .98 N .
weight of metal in oil = .98 - .097
= .883 N .
=