Question

A 547-mLmL sample of unknown HCl HCl solution reacts completely with Na2CO3Na2CO3 to form 17.1 gg CO2CO2. What was the concentration of the HClHCl solution?

Answer 1

Answer:

the required concentration is 1.52 M

2 HCl + Na2CO3 -----> CO2 + H2O + NaCl

2 moles HCl reacts to form 1 mole of CO2 .

no. of moles of CO2 = 20.1/ 44.1 = 0.455

no. of moles of HCl = 0.455* 2 = 0.911 mole (molar ratio =2 from equation)

con. of HCl =no. of moles/volume in liter

=0.911/ 0.597 = 1.52 M