Light is produced by the change of state of energy of an electron. Within an atom, there are multiple electron "shells". 'Excited' atoms are those where the electrons are moving in between shells. The electrons move because they are given energy enough to move to a different shell; however, they are unstable and cannot remain in their new position. When moving back to its original shell, the electron loses energy - but energy can't be created nor destroyed so they release a photon.
There's other ways light may be produced, but always it is produced as a result of transmission of energy (in some form). Also, light is usually produced in conjunction with other forms of energy such as sound or heat.
(a) The lunch angle is 64.8⁰
(b) The initial speed of the pass when the angle of projection is 25⁰ is 21.2 m/s
(c) The time of flight of the bullet is 1.83 s
<em>"Your question is not complete, it seems to be missing the chart i uploaded".</em>
The given parameters include;
time of flight, T = 3.97 s
initial velocity, u = 21.5 m/s
(a) The lunch angle is calculated from the equation of motion of time of flight;
(b) the initial speed of the pass when the angle of projection is 25⁰ and range of 35 m, is calculated as follows;
(c) The time of flight of the bullet is calculated as;
Learn more here: brainly.com/question/20689870
Answer:
60 cycles
Explanation:
The first thing we must do to solve the problem is to find how many cycles are presented in 1cm by multiplying the frequency by the base time of the
K=time base=2ms/cm=2x10-3s/cm
f=frecuency=3000s^-1
N=fk
N=(3000)(2x10^-3)=6cycles/cm
Ntot=6x10=60cycles
Answer:
Explanation:
a )
in the regions r < R₁
charge q inside sphere of radius R₁ = 0
Applying gauss's law for electric field E at distance r <R₁
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = q / ε₀ = 0 / ε₀
E = 0
Applying gauss's law for electric field E at distance R₁ < r < R₂ .
charge q inside sphere of radius R₁ = q₁
Applying gauss's law for electric field E at distance R₁ < r < R₂
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = q₁ / ε₀
E = q₁ / 4πε₀
in the regions r> R₂
charge q inside sphere of radius R₂ = (q₁ + q₂)
Applying gauss's law for electric field E at distance r > R₂
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = (q₁ + q₂) / ε₀
E = (q₁ + q₂) /4π ε₀
b )
For electric flux to be zero at r > R₂
(q₁ + q₂) /4π ε₀ = 0
q₁ + q₂ = 0
q₁ / q₂ = - 1 .
Answer:
Lifeless because of the lack of rain