<span>(2.09 mL) x (1.592 g/mL) / (227.0871 g C3H5O9N3/mol) = 0.014652 mole C3H5O9N
4 moles C3H5O9N produce 12 + 6 + 1 + 10 = 29 moles of gases, so:
(0.014652 mole C3H5O9N) x (29/4) = 0.106 mole of gases
(b)
(0.106 mol) x (46 L/mol) = 4.88 L gases
(c)
(0.014652 mole C3H5O9N) x (6/4) x (28.0134 g/mol) = 0.616 g N2</span>
Molarity can be defined as the number of moles of substance dissolved in 1 L of solution.
In the given question ,
number of LiOH moles - 1.495 mol
Dissolved volume - 750 mL
molarity is calculated for 1 L = 1000 mL
In 750 mL - 1.495 mol of LiOH is dissolved
Therefore in 1000 mL - 1.495 mol / 750 mL x 1000 = 1.99 mol
Ans is B.Bromine. Only two elements are liquid at room temperature ( mercury and Bromine) . Helium and chlorine, arsenic are gases.
Answer:
2 electrons
Explanation:
Since the atomic structure is at it's neutral state
E = HF, where H is Planck's constant, 6.63 x 10 - 34 j.s
