Question

A load of 500N is carried by 200N effort in a simple machine having load distance 3m Calculate effort distance.​

Answer 1

Answer:

2.5 m

Explanation:

Load ( L ) = 500 N

Effort ( E ) = 200 N

Load distance ( LD ) = 3 m

Effort distance ( ED ) = ?

Now, Let's find the Effort distance ( ED )

We know that,

Output work = Input work

i.e L × LD = E × ED

plug the values

$500 \times 3 = 200 \times ED$

multiply the numbers

$1500 = 200 \times ED$

Swipe the sides of the equation

$200 \: ED \: = 500$

Divide both sides of the equation by 200

$\frac{200 \: ED}{200} = \frac{500}{200}$

Calculate

$ED\: = 2.5 \: m$

Hope this helps..

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