All categories

4 years ago

Why is Jupiter so much larger than Earth? Check all that apply.

Chemistry

2 answers:

Debora [2.8K]4 years ago

6 0

Answer:

The answer is A, C and E

also

1, 3 and 5

Explanation:

Why is Jupiter so much larger than Earth? Check all that apply.

Inner planets were created at higher velocities.

Outer planets have less gravity than inner ones.

Outer planets attracted helium, hydrogen, and other gasses.

Inner planets formed where temperatures were cooler.

Gases escaped from inner planets and not from outer ones.

SIZIF [17.4K]4 years ago

3 0

Answer:

The answer is A, C and E

also

1, 3 and 5

Explanation:

You might be interested in

-The picture goes to Activity 2

Alborosie

Answer:

Activity 1: Since the only forces apposing the upward movement of the load are gravity and air resistance the formulas of which can both be solved with weight then with constant variables for gravity and air, effort IS directly proportional to weight.

Activity 2:

Inclined plane.

to make lifting easier; raising or lowering a load.

Explanation:

hope this helps.

4 0

4 years ago

Read 2 more answers

What are the two parts of a solution?

Vlad [161]

The 2 parts or components that make up a solution would be the solute and the solvent.

6 0

3 years ago

Problem page gaseous ethane ch3ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o

iVinArrow [24]

$m(\text{CO}_2) = 2.24 \; \text{g}$

Ethene react with oxygen at a $2 : 7$ molar ratio:

$2\; \text{C}_2 \text{H}_6 (g) + 7\; \text{O}_2 (g) \to 6\; \text{H}_2{O} (g) + 4\; \text{CO}_2 (g)$

Convert the quantity of each reactant supplied to number of moles of particles:

$n(\text{C}_2\text{H}_6) = 0.60 \; \text{g} / 28.05 \; \text{g} \cdot \text{mol}^{-1} = 0.0214 \; \text{mol}$
$n(\text{O}_2) = 3.27 \; \text{g} / 32.00 \; \text{g} \cdot \text{mol}^{-1} = 0.102 \; \text{mol}$

The question stated not whether both reactants were used up in this process. Thus start by testing the assumption that e.g., ethene was used up while some oxygen gas were left unreacted (ethene as the <em>limiting </em>reagent.) Under this assumption, the relative availability of the two species, $n(\text{C}_2 \text{H}_6) /2$ and $n(\text{O}_2) /7$ (as seen in the balanced chemical equation) shall satisfy the relationship

$n(\text{O}_2) / 7 - n(\text{C}_2 \text{H}_6) / 2 > 0$

In other words,

$n(\text{O}_2)/7 > n(\text{C}_2 \text{H}_6)/2$

$n(\text{C}_2 \text{H}_6) / n(\text{O}_2) < 2/7 \approx 0.286$

Evaluating the expression $n(\text{C}_2 \text{H}_6) / n(\text{O}_2)$ with data given in the question yields approximately $0.210 < 0.286$ , which does satisfy the relationship. Hence the assumption holds and ethene is the limiting reactant.

The quantity of a reactant produced in a chemical reaction is related to its stoichiometric (of relating to proportions) relationship with the limiting reactant (or any of the reactants in case of more than one limiting reactant.) For this scenario, given the molar ratio $n(\text{C}_2\text{H}_6) : n( \text{CO}_2) = 2:4$ ,