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Lunna [17]
3 years ago
12

In a relative frequency distribution, what should the relative frequencies add up to?

Mathematics
1 answer:
VMariaS [17]3 years ago
8 0

Answer:

A. 1

Step-by-step explanation:

The relative frequency is calculated by dividing the frequency of respective class to the total frequency. i.e R.f=f/∑f.

Hence, the relative frequencies can never be add up to total number of observations because it is computed from taking the proportion of frequency and total number of observation. The relative frequencies thus add up to 1.

For example we are given the frequencies for 3 classes as 6,4,2 and computed relative frequencies of these 3 classes are 6/12, 4/12 and 2/12.

Now adding these three relative frequencies 6/12+4/12+2/12=6+4+2/12=12/12=1.

Thus, the relative frequencies add up to 1.

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What is mean of 8,3,3,7 and 4
Marina86 [1]
The mean is the average of the numbers. To obtain it, you add all the numbers together and divide by the number of numbers. So:

8+3+3+7+4= 25

25:5= 5

So the answer is: the mean is 5.
3 0
3 years ago
If 50 percent of x=66 then x =
sasho [114]

Answer:

132

Step-by-step explanation:

50 % means half

so 66 is half of whatever x is.

to find x you have to multiply 66 by 2 or add 66 to 66 which will give you 132 either way.

<em>Hope this helps you! have an amazing day :)</em>

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A student got 68% of the questions correct on the Social Studies test. If there were 50 questions, how many questions did they g
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The answer is 34.

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428 × (-23 ) + (-428 )× (-223)=<br> can you answer it with steps it would be a great help for me
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Answer:

-935160312

Step-by-step explanation:

3 0
3 years ago
(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde
monitta

Using the distance formula, d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2  } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2}  \\d=\sqrt{36+4} \\d=\sqrt{40} \\

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

<em>Five or more, let it soar. Four or less, let it rest.</em>

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

8 0
2 years ago
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