The fourth most abundant element in terms of mass is Carbon.
The first, second, and third most abundant element in terms of mass are Hydrogen, Helium, and Oxygen, respectively.
Hope this helps~
Answer:
.
Explanation:
Look up the relative atomic mass of 
, 
, and 
on a modern periodic table:
Calculate the molecular mass of 
and 
:
;
.
Given the mass 
of and produced, calculate the number of moles of molecules that were produced:
;
.
Calculate the number of moles of atoms and atoms in these and molecules.
- Each molecule contains one atom. Therefore, that
of 
contains 
of 
atoms. - Each molecule contains two atoms. Therefore, that of
contains 
of 
atoms.
The combustion reaction here include two reactants: the hydrocarbon and 
.
As the name suggests, hydrocarbons contain only atoms and atoms. On the other hand, contains only atoms.
Therefore, all the and atoms in those and molecules are from the unknown hydrocarbon. (With a similar logic, all the atoms in those combustion products are from .)
In other words, that 
of this unknown hydrocarbon molecules contains:
Hence, each of these hydrocarbon molecules would contain 
carbon atoms and 
hydrogen atoms.
The molecular formula of this hydrocarbon would be 
.
<h3><u>Answer;</u></h3>
357 mg/mL
<h3><u>Explanation;</u></h3>
- Solubility is defined to be the maximum amount of solute that will dissolve in a given amount of solvent at a specific temperature. The solubility of a salt is one of many physical properties that depend on temperature.
- At room temperature 25 °C, the solubility of salt or Sodium Chloride is 357 mg/mL.
- For many solutes, increasing the temperature increases the solubility of the solute. The solubility of sodium chloride or table salt is only slightly affected by temperature increase.
The name for the ionic compound Cs2S is Cesium sulfide.
Answer:
Half life is 6 years.
Explanation:
T½ = In2 / λ
Where λ = decay constant.
But N = No * e^-λt
Where N = final mass after a certain period of time
No = initial mass
T = time
N = 0.625g
No = 10g
t = 24 years
N = No* e^-λt
N / No = e^-λt
λ = -( 1 / t) In N / No (inverse of e is In. Check logarithmic rules)
λ = -(1 / 24) * In (0.625/10)
λ = -0.04167 * In(0.0625)
λ = -0.04167 * (-2.77)
λ = 0.1154
T½ = In2 / λ
T½ = 0.693 / 0.1154
T½ = 6.00 years.
The half life of radioactive cobalt-60 is 6 years
.
.
.
of