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Harrizon [31]
3 years ago
15

How many bonds are between the two carbon atoms in C2H2?

Chemistry
1 answer:
julsineya [31]3 years ago
6 0
C2H2 has 3 bonds between two carbon atoms
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Which definition best describes a titration?
Juliette [100K]

Answer:

the answer is C

Explanation:

4 0
3 years ago
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What are the sign and magnitude of the charge of atom containing 14 protons, 15 neutrons, and 12 electrons?
Karo-lina-s [1.5K]
<span>We know that protons gives positive charge, neutrons no charge and electrons negative, then +14 - 12 = +2 So the charge of the atom is sign positive and magnitude 2</span>
7 0
3 years ago
Estimate the optimal number of neutrons for a nucleus containing 70 protons.
DochEvi [55]

Atomic number 70

weight 173

number of neutron = weight - Atomic number

= 173 -70

=103

6 0
3 years ago
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The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is ________ M sodium ion and ________ M sulfate i
omeli [17]

Answer:

The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion.  (option E)

Explanation:

Step 1: Data given

Volume = 500 mL = 0.500 L

The concentration sodium sulfate = 2.104 M

Step 2: The equation

Na2SO4 → 2Na+ + SO4^2-

For 1 mol Na2SO4 we have 2 moles sodium ion (Na+) and 1 mol sulfate ion (SO4^2-)

Step 3: Calculate the concentration of the ions

[Na+] = 2*2.104 M = 4.208 M

[SO4^2-] = 1*2.104 M = 2.104 M

The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion.  (option E)

8 0
2 years ago
How much faster does helium escape through a porous container than ozone?
otez555 [7]
According to Graham's Law ," the rates of effusion or diffusion of two gases are inversely proportional to the square root of their molecular masses at given pressure and temperature".

                                r₁ / r₂  =  \sqrt{M2 / M1}   ---- (1)

r₁    =  Rate of effusion of He

r₂    =  Rate of Effusion of O₃

M₁  =  Molecular Mass of He  =  4 g/mol

M₂  =  Molecular Mass of O₃  =  48 g/mol

Putting values in eq. 1,

                                r₁ / r₂  =  \sqrt{48 / 4}

                                r₁ / r₂  =  \sqrt{12}

                                r₁ / r₂  =  3.46

Result:
          Therefore, Helium will effuse 3.46 times more faster than Ozone.
4 0
3 years ago
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