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goldfiish [28.3K]
3 years ago
13

A) The change in the internal energy of a system that absorbs 2,500 J of heat and that does 7,655 J of work on the surroundings

is _________ J.
b) The ΔE of a system that absorbs 12.4J of heat and does 4.2 J of work on the surroundings is __________ J.
Chemistry
1 answer:
Phoenix [80]3 years ago
5 0

Answers:

a) 10155 J

b) 16.6 J

Explanation:

According to the First Law of Thermodynamics we have:

\Delta E=Q + W

Where:

\Delta E is the total change in the internal energy of a system

Q is the heat exchanged between the system and its surroundings

W is the work done on the system

a) In this case Q=2500 J and W=7655 J, hence:

\Delta E=2500 J + 7655 J=10155 J

b) In this case Q=12.4 J and W=4.2 J, hence:

\Delta E=12.4 J + 4.2 J=16.6 J

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Hello,

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