1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maks197457 [2]
3 years ago
15

Which two conditions would result in the strongest electric force between charged objects

Physics
2 answers:
Travka [436]3 years ago
6 0

It’s objects are close together and object are insulators with unbalanced charges

Explanation: just trust me :)

miv72 [106K]3 years ago
4 0

Answer:

A and B

Explanation:

You might be interested in
What is the direction of propagation of the wave if E⃗ =Ei^,B⃗ =−Bj^. Express the direction of the propagation vector, P⃗ , as a
nataly862011 [7]

Answer with Explanation:

We are given that

Electric field vector=\vec{E}=E\hat{i}

Magnetic field vector=\vec{B}=-B\hat{j}

We have to find the direction of propagation of the wave.

We know that  

The direction of propagation of wave=\vec{E}\times \vec{B}

The direction of propagation of wave=\hat{i}\times (-\hat{j})=-\hat{k}

Because (\hat{i}\times \hat{j}=\hat{k})

The  wave propagate in -z direction.

Therefore, the component of the vector is (0,0,-1).

Hence, the direction of the propagation of wave is - z direction and component of direction of propagation vector is (0,0,-1).

6 0
4 years ago
Pedro uses a bar magnet to pick up a nail. He then
lisabon 2012 [21]

The nail has become a temporary magnet, while the

bar magnet remains a permanent magnet.

7 0
3 years ago
Read 2 more answers
Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1360 N. Assume that the play
Alona [7]

Answer:

7.59Ns

Explanation:

Given parameters:

Force  = 1360N

Time of contact  = 5.85 x 10⁻³s

Unknown:

Impulse  = ?

Solution:

The impulse of the ball is given as:

        Impulse  = Force x time

       Impulse  = 1360 x 5.85 x 10⁻³ = 7.59Ns

4 0
3 years ago
A car slows down at -5.00 m/s² until it comes to a stop after travelling 15.0 m. What was the initial speed of the car?
lapo4ka [179]
<h2>Answer: 12.24m/s</h2>

According to <u>kinematics</u> this situation is described as a uniformly accelerated rectilinear motion. This means the acceleration while the car is in motion is constant.

Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:

V_{f}^{2}-V_{o}^{2}=2.a.d   (1)

Where:

V_{f} is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.

V_{o} is the Initial Velocity, the value we want to find

a is the constant acceleration of the car (the negative sign means the car is decelerating)

d is the distance traveled by the car

Now, let's substitute the known values in equation (1) and find V_{o}:

0-V_{o}^{2}=2(-5m/{s}^{2})(15m)    (2)

-V_{o}^{2}=-150{m}^{2}/{s}^{2}    (3)

Multiplying by -1 on both sides of the equation:

V_{o}^{2}=150{m}^{2}/{s}^{2}    (4)

V_{o}=\sqrt{150{m}^{2}/{s}^{2}}    (5)

Finally:

V_{o}=12.24m/s >>>This is the Initial velocity of the car

5 0
3 years ago
determine the greates possile acceleration of the 975 kg race car so that its front wheels do not leace the gorund
wolverine [178]

<u>Answer</u>:

The greatest possible acceleration of the car is a_G= 6.78 m/s^2

<u>Explanation</u>:

N_A+N_B-Mg = 0

-N_Aa +N_B(b-a)- \mu_s N_Bh - \mu_s N_Ah = 0

0.8N_B +0.8N_A = 975a_G

N_A+N_B = 9564.75 -------------(1)

-N_A(1.82) + N_B(2.20 -1.82) -0.9N_B(0.55)-0.8N_A(0.55)=0

-N_A(1.82) +0.38 N_B -0.44N_B -0.44N_A=0

-2.26N_A -0.06N_B= 0 ----------------(2)

Solving the equation (1) and(2)

N_A + N_B = 9564.75

-2.26N_A-0.06N_B=0

N_A = -260.85N

N_B = 9825.60N

\mu_s N_B + \mu_s N_A = 975a_G

0.8(9825.60)+0.8(-260.85) = 975a_Ga_G=\frac{7651.8}{975}a_G_1=7.4848m/s^2

Next lets assume that the front wheels contact with the ground N_A = 0

F_B = Ma_G

N_B = M_g

N_B - M_g = 0

N_B(b-a) –F_Bh = 0

F_B = 975a_G

N_B-975(9.8) = 0

N_B=9564.75N

9564.75(2.20 -1.82) -F_B(0.55)=0

\frac{3634.605}{0.55}=F_B

F_B = 6608.3

F_B = Ma_G

6608.3 = 975a_G

a_G = 6.7778 m/s^2

a_G_2 = 6.78m/s^2

Choosing the critical case

a_G = min(a_G_1 ,a_G_2)

a_G = min(7.848, 6.78)

a_G= 6.78 m/s^2

3 0
4 years ago
Other questions:
  • a lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block
    6·1 answer
  • Which of the following describes an air mass with the symbol c t?
    14·1 answer
  • 4. An object moves in a circular path at a constant speed. Compare the direction of the object’s velocity and acceleration vecto
    12·1 answer
  • Someone please help me will give BRAILIEST!!!!!
    10·1 answer
  • A 88 kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.
    6·1 answer
  • What is the unit for coefficient of kinetic friction?
    6·1 answer
  • The main difference between a chest and a bounce pass is what?
    12·2 answers
  • what is the average gravitational force of attraction between the earth and the sun? the earth averages a distance of about 150
    8·1 answer
  • An object is moving with an initial velocity of 3.3m/s it is subject to a constant acceleration of 3.7 m/s2 for 10 s. How far wi
    5·1 answer
  • Wilbur ran 1-kilometer. Then he ran 500 meters. How many meters did Wilbur run all together?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!