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maks197457 [2]
3 years ago
15

Which two conditions would result in the strongest electric force between charged objects

Physics
2 answers:
Travka [436]3 years ago
6 0

It’s objects are close together and object are insulators with unbalanced charges

Explanation: just trust me :)

miv72 [106K]3 years ago
4 0

Answer:

A and B

Explanation:

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Answer:

c. 1.11 m/s down

Explanation:

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m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Assuming the balloon and projectile are originally at rest:

(90 kg) (0 m/s) + (10 kg) (0 m/s) = (90 kg) v + (10 kg) (10 m/s)

0 kg m/s = (90 kg) v + 100 kg m/s

v = -1.11 m/s

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A bicyclist moves at a constant speed of 4 ms-1 how long will it take for the bicyclists to move 36m?
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Suppose you are testing the buoyancy of different objects. Study the table and choose the object with the greatest buoyant force
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In short, Object 3 would have the largest Buoyant Force

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7 0
3 years ago
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A 65 kg students is walking on a slackline, a length of webbing stretched between two trees. the line stretches and sags so that
polet [3.4K]

Answer : Tension in the line = 936.7 N

Explanation :

It is given that,

Mass of student, m = 65 kg

The angle between slackline and horizontal, \theta=20^0

The two forces that acts are :

(i) Tension

(ii) Weight

So, from the figure it is clear that :

mg=2T\ sin\ \theta

T=\dfrac{mg}{2\ sin\theta}

T=\dfrac{65\ kg\times 9.8\ m/s^2}{2(sin\ 20)}

T=936.7\ N

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5 0
3 years ago
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a force 2.4E2 N exists between a positive charge of 8E-5 C and a positive charge of 3E-5 C. What distance separates the charges?
Verdich [7]

The distance between the two charges is 0.3 m

Explanation:

The electrostatic force between two charged objects is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the charges of the two objects

r is the separation between the two charges

In this problem, we are given the following:

q_1 = 8\cdot 10^{-5} C

q_2 = 3\cdot 10^{-5} C

F=2.4\cdot 10^2 N

Therefore, we can rearrange the equation to solve for r, the distance between the two charges:

r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(8.99\cdot 10^9)(8\cdot 10^{-5})(3\cdot 10^{-5})}{2.4\cdot 10^2}}=0.3 m

Learn more about electrostatic force:

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6 0
3 years ago
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