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Sergeu [11.5K]
2 years ago
8

For 2Na (s) + Cl2(g) - 2NaCI (s) ,how many grams of sodium Chloride will be made from 115 g of sodium metal when reacted with ex

cess chlorine gas ?
Chemistry
1 answer:
Solnce55 [7]2 years ago
5 0

<u>Given:</u>

Mass of Na = 115 g

Excess Cl2

<u>To determine:</u>

Mass of NaCl produced

<u>Explanation:</u>

Given reaction is-

2Na(s) + Cl2(g) → 2NaCl(s)

Since Cl2 is in excess, Na will be the limiting reagent

As per the reaction stoichiometry Na:NaCl = 1:1

i.e. moles of Na reacted = moles of NaCl formed

Now, # moles of Na = mass of Na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

Therefore, moles of NaCl = 5

Molar mass of NaCl = 58 g/mol

Mass of NaCl = 5 moles * 58 g.mol-1 = 290 g

Ans: Amount of Nacl produced = 290 g

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