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Anestetic [448]
3 years ago
10

A sample of phosphonitrilic bromide, PNBr2, contains 2.01 mol of the compound. Determine the amount (in mol) of each element pre

sent and the number of atoms of each element present in the sample.
Chemistry
2 answers:
ipn [44]3 years ago
7 0

Answer:

For 2.01 moles PNBr2 we have 1.21 *10^24 molecules

P =  1.21 *10^24 atoms

N = 1.21 *10^24 atoms

Br = 2.42*10^24 atoms

Explanation:

Step 1: Data given

Number of moles of PNBr2 = 2.01 moles

Step 2: Calculate moles per element

For 1 mol PNBr2 we have 1 mol P, 1 mol N and 2 moles Br

For 2.01 moles PNBr2 we have:

P = 2.01 moles

N = 2.01 moles

Br = 2* 2.01 = 4.02 moles

Step 3: Calculate atoms of each element

For 2.01 moles PNBr2 we have 6.022 *10^23 * 2.01 = 1.21 *10^24 molecules

P = 2.01 moles = 6.022 *10^23 * 2.01 = 1.21 *10^24 atoms

N = 2.01 moles = 6.022 *10^23 * 2.01 = 1.21 *10^24 atoms

Br = 4.02 moles = 6.022 *10^23 * 4.02 = 2.42*10^24 atoms

nordsb [41]3 years ago
6 0

Answer:

2.01 moles of P → 1.21×10²⁴ atoms

2.01 moles of N → 1.21×10²⁴ atoms

4.02 moles of Br → 2.42×10²⁴ atoms

Explanation:

We begin from this relation:

1 mol of PNBr₂ has 1 mol of P, 1 mol of N and 2 moles of Br

Then 2.01 moles of PNBr₂ will have:

2.01 moles of P

2.01 moles of N

4.02 moles of Br

To determine the number of atoms, we use the relation:

1 mol has NA (6.02×10²³) atoms

Then: 2.01 moles of P will have (2.01  . NA) = 1.21×10²⁴ atoms

2.01 moles of N (2.01  . NA) = 1.21×10²⁴ atoms

4.02 moles of Br (4.02 . NA) = 2.42×10²⁴ atoms

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Answer:

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Explanation:

I pretty much covered it in my answer!

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Alpha particle is equivalent to B. Helium atom (2 protons, 2 neutrons) 
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How many sulfur atoms are generated when 9.42 moles of H2S react according to the following equation: 2H2S+SO2→3S+2H2O
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Answer:

A) 8.51 × 10²⁴  

Explanation:

1. Gather all the information

            2H₂S + SO₂ ⟶ 3S + 2H₂O

n/mol:   9.42

2. Calculate the moles of S atoms

The molar ratio is 3 mol S:2 mol H₂S

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3. Calculate the atoms of S

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#PLATOFAM
Vsevolod [243]
Ketones and aldehydes are simple compounds that contain a carbonyl group (a carbon-oxygen double bond). They are considered "simple" because they do not have reactive groups like −OH or −Cl attached directly to the carbon atom in the carbonyl group, as in carboxylic acids containing −COOH<span>.

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ΔG° at 450. K is -198.86kJ/mol

The following is the relationship between  ΔG°,  ΔH, and  ΔS°:

ΔH-T ΔS = ΔG

where  ΔG represents the common Gibbs free energy.

the enthalpy change,  ΔH

The temperature in kelvin is T.

Entropy change is  ΔS.

ΔG° = -206 kJ/mol

ΔH° equals -220 kJ/mol

T = 298 K

Using the formula, we obtain:

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220 kJ/mol +206 kJ/mol =T ΔS°.

-T ΔS = 14 kJ/mol

for ΔS-14/298

ΔS=0.047 kJ/mol.K

450K for the temperature Completing a formula with values

ΔG° = (450K)(-0.047kJ/mol)-220kJ/mol

ΔG° = -220 kJ/mol + 21.14 kJ/mol.

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