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Anna35 [415]
4 years ago
6

Balance the following skeleton reaction and identify the oxidizing and reducing agents: H2S(g) + NO3 ---->’ S8(s) + NO(g) [ac

idic] Include the states for each reactant and product in the balanced chemical equation. Do not include the states when identifying the oxidizing and reducing agents.

Chemistry
1 answer:
disa [49]4 years ago
6 0

Answer : Oxidizing agent is NO^-_3 and Reducing agent is H_2S

Explanation :

The given unbalanced redox reaction is,

H_2S(g)+NO^-_3(aq)\rightarrow S_8(s)+NO(g)

In acidic medium, the balanced redox reaction is,

24H_2S(g)+6NO^-_3(aq)16H^+(aq)\rightarrow 3S_8(s)+16NO(g)32H_2O(l)

Oxidizing agent : Oxidizing agents are those agent which oxidizes other substance and itself get reduced.

Reducing agent : Reducing agents are those agent which reduces other substance and itself get oxidized.

In this redox reaction, NO^-_3 is an oxidizing agent and H_2S is a reducing agent.

The redox reaction is also shown below.


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QveST [7]
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3 0
4 years ago
The amount of I−3(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O2−3(aq
Pavlova-9 [17]

Answer : The molarity of I_3^- in the solution is, 0.128 M

Explanation :

The given balanced chemical reaction is,

2S_2O_2^{-3}(aq)+I_3(aq)\rightarrow S_4O_2^{-6}(aq)+3I^-(aq)

First we have to calculate the moles of Na_2S_2O_3.

\text{Moles of }Na_2S_2O_3=\text{Molarity of }Na_2S_2O_3\times \text{Volume of solution}

\text{Moles of }Na_2S_2O_3=0.260mole/L\times 0.0296L=0.007696mole

Conversion used : (1 L = 1000 ml)

Now we have to calculate the moles of I_3^-.

From the balanced chemical reaction, we conclude that

As, 2 moles of S_2O_2^{-3} react with 1 mole of I_3^-

So, 0.007696 moles of S_2O_2^{-3} react with \frac{0.007696}{2}=0.003848 mole of I_3^-

The moles of I_3^- = 0.003848 mole

Now we have to calculate the molarity of I_3^-.

\text{Molarity of }I_3^-=\frac{\text{Moles of }I_3^-}{\text{Volume of solution}}

Now put all the given values in this formula, we get:

\text{Molarity of }I_3^-=\frac{0.003848mole}{0.03L}=0.128mole/L=0.128M

Therefore, the molarity of I_3^- in the solution is, 0.128 M

8 0
3 years ago
Which of the following will increase polymer strain to failure
Blizzard [7]

increase Polymer strain to failure is given below.

Explanation:

  • Strain to failure gives the measure of how much the specimen is elongated to failure. By this it means that, it you have strain to failure of 3% measured in specimen of length 100 mm, the material will fail when it it elongated 3 mm, as experimented in tensile test. Therefore, for a material with higher strain to failure rate, the ductility is higher and tensile strength is lower.

  • Tensile strength means the maximum mechanical stress (i.e. applied force divided by (initial) cross-section area of the specimen tested) during a tensile test, which is not directly correlated to the deformability or strain at failure or break since the tensile strength also is affected by the stiffness of the material. Therefore a ductile material might deform on a lower mechanical stress level than a stiffer one (this is the usual case), meaning its tensile strength is lower although its deformability is higher.
  • Therefore, for a material with higher strain to failure rate, the ductility is higher and tensile strength is lower.

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4 years ago
True or False: Neutrons have both a positive and negative charge
uysha [10]

Answer:

false

Explanation:

7 0
3 years ago
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Alborosie

Answer:

A

Explanation:

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