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Nina [5.8K]
3 years ago
8

Find the speed of a bicyclist who took an hour and a half to travel 10km

Physics
1 answer:
Natalija [7]3 years ago
7 0

distance = 10km

time = 1 1/2 = 3/2 hours

speed = distance/time = 10 / 3/2 = 20/3 = 6.67 Km/h

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A proton has been accelerated from rest through a potential difference of -1000 v . part a what is the proton's kinetic energy,
wlad13 [49]
We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:
\Delta U + \Delta K=0
which means
\Delta K = - \Delta U
The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (\Delta V=-1000 V):
\Delta U = q \Delta V=(1 eV)(-1000 V)=-1000 eV
Therefore, the kinetic energy gained by the proton is
\Delta K = -(-1000 eV)=1000 eV
<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>
4 0
3 years ago
Read 2 more answers
An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro
Mashutka [201]

1) The distance travelled by the electron is 1\cdot 10^{17} m

2) The time taken is 4.0\cdot 10^{10}s

Explanation:

1)

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

u=5\cdot 10^6 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

a=-1.25\cdot 10^{-4} m/s^2 is the acceleration

Solving for s, we find the distance travelled:

s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m

2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

u=5\cdot 10^6 m/s

v = 0

a=-1.25\cdot 10^{-4} m/s^2

And solving for t, we find the time taken:

t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
If the speed of a ball increased from 1m/s to 4m/s, by how much would the kinetic energy increase
GREYUIT [131]
In 16 times
KE= o.5 m times V squared
6 0
3 years ago
If a light Ray is reflected off the shiny surface at 170 degrees at what angle did the light-ray first strike the surface
garri49 [273]
10 degrees would be your answer hope this helps!

4 0
3 years ago
Read 2 more answers
The temperature of a solution will be estimated by taking n independent readings and averaging them. Each reading is unbiased, w
Viktor [21]

Answer:

68 readings.

Explanation:

We need to take this problem as a statistic problem where the normal distribution table help us.

We can start considerating that X is the temperature of the solution, then

0.9 = P(|\bar{x}-\mu|

0.9 = P(\frac{|\bar{x}-\mu|}{\frac{\sigma}{\sqrt{n}}}

0.9 = P(|Z|

For a confidence level of 90% our Z_{critic} is 1.645

Therefore,

\frac{0.1}{\frac{\sigma}{\sqrt{n}}} = 1.645

Substituting for \sigma = 5 and re-arrange for n, we have that n is equal to

n=(\frac{1.645\sigma}{0.1})^2

n=\frac{(1.645)^2(0.5)^2}{0.1^2}

n=67.65

n=68

We need to make 68 readings for have a probability of 90% and our average is within 0.1\°\frac

3 0
3 years ago
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