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BigorU [14]
3 years ago
13

A 60kg block rests on rough horizontal ground. A rope is

Physics
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

30

Explanation:

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The peak current through a resistor is 2. 0 aa. part a what is the peak current if the resistance rr is doubled?
timofeeve [1]

When the resistance R is doubled, I = 1 A

One of the most fundamental and significant principles controlling electrical and electronic circuits is called Ohm's Law. For a linear device, it relates current, voltage, and resistance.

According to Ohm's Law, the current flowing through a circuit is inversely proportional to the resistance in the circuit and directly proportional to the applied potential difference.

Ohm's law can be written mathematically as follows:

V = IR

Where:

   V = voltage expressed in Volts

   I = current expressed in Amps

   R = resistance expressed in Ohms

If any two quantities are known, the third can be computed by manipulating the formula.

   I= V/R

   R= V/I

To know more about Ohm's law refer:

brainly.com/question/796939

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8 0
2 years ago
PLEASE HELP!
lutik1710 [3]

Answer:

Thats her fault.........................b

Explanation:

6 0
3 years ago
Elaborate on the suitability of "cola" type drinks to polish chrome surfaces.
nexus9112 [7]
The answer is t<span>he phosphoric acid in cola easily removes dirt and grime.   The </span>"cola" type drinks is suitable to polish chrome surfaces. Cola contains a very diluted solution of phosphoric acid, which can  remove rust, dirt, and grime from chrome surface. 
3 0
4 years ago
a bungee jumper momentarily comes to rest at the bottom of the dive before he springs back upward. at that moment, is the bungee
barxatty [35]

Answer:

Explanation:

No, the bungee jumper is not at equilibrium.

This can be explained when we consider a bungee jumper as a mass that is undergoing simple harmonic motion. At extreme points i.e. at the bottom, the velocity of the jumper is zero but not the acceleration because it is acting in the opposite direction that is why the jumper moves upward.

3 0
4 years ago
Read 2 more answers
A mass is bobbing up and down on a spring. If you increase the amplitude of the motion, how does this affect the time for one os
NikAS [45]

Answer:

It will not change

Explanation:

The period of oscillation of a mass-spring system is given by

T=2\pi \sqrt{\frac{m}{k}}

where

T is the period

m is the mass hanging on the spring

k is the spring constant

As we see from the formula, the period of oscillation does not depend on the amplitude of the motion: therefore, if we change the amplitude, the time for one oscillation will not change.

6 0
3 years ago
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