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BigorU [14]
3 years ago
13

A 60kg block rests on rough horizontal ground. A rope is

Physics
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

30

Explanation:

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Why do the passengers in high-altitude jet planes feel the sensation of weight while passengers in an orbiting space vehicle, su
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Passengers in an aircraft are subject to the Normal and Gravity Force acting on them at a low 'orbit', so tiny that it can be many times compared to the same surface of the earth when speaking in general terms.

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Remember that the Force of Gravity is given under the principle

F_g = \frac{GMm}{r^2}

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who brought astronomy out of the dark ages by declaring: "finally we shall place the sun himself at the center of the universe.
solong [7]

Nicolaus Copernicus was the one who brought astronomy out of the dark ages.

In one of his books "On the Revolutions of the Heavenly Bodies", he published the renowned line which declares his theory.

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To know more about the Heliocentric system refer to the link brainly.com/question/3491738?referrer=searchResults.

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6 0
2 years ago
One small speaker is placed 3m to the east of a second speaker, and a listener stands 4m directly south of one of the speakers.
alexandr402 [8]

Answer:

The value is \lambda  =  2 \  m

Explanation:

From the question we are told that

     The distance of the speaker  from the  second speaker  to the east is  d = 3 \  m

      The distance of the speaker  from the listener  to the south is     a = 4 \  m

Generally given that if the speaker move in any direction, their sound become  louder , it then mean that the position of the listener of minimum sound (i.e a position of minima ) ,

Generally the path difference of the sound produce by both speaker at a position of minima is mathematically represented as

              y =  \frac{\lambda}{2}

Generally considering the orientation  of the speakers and applying Pythagoras theorem we see that  distance from the second speaker to the listener  is mathematically represented as

             b =  \sqrt{d^ 2 + a^2 }

=>           b =  \sqrt{3^ 2 + 4^2 }

=>           b = 5

Generally the path difference between the two speaker with respect to the  listener is  

              y =  b - a

=>           y = 5 - 4

=>           y = 1

So  

              1 =  \frac{\lambda}{2}

=>           \lambda  =  2 \  m

4 0
3 years ago
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