Answer:
4.48×10⁶ dm³
Explanation:
We'll begin by converting 23.4 tonnes to grams (g). This can be obtained as follow:
1 tonne = 10⁶ g
Therefore,
23.4 tonnes = 23.4 × 10⁶
23.4 tonnes = 2.34×10⁷ g
Thus, 23.4 tonnes is equivalent to 2.34×10⁷ g
Next, we shall determine the number of mole in 2.34×10⁷ g of NaCl. This can be obtained as follow:
Mass NaCl = 2.34×10⁷ g
Molar mass of NaCl = 58.5 g/mol
Mole of NaCl =?
Mole = mass / molar mass
Mole of NaCl = 2.34×10⁷ / 58.5
Mole of NaCl = 4×10⁵ moles
Next, we shall determine the number of mole of chlorine, Cl₂ produced from the reaction. This can be obtained as follow:
2NaCl —> 2Na + Cl₂
From the balanced equation above,
2 moles of NaCl reacted to produce 1 mole of Cl₂.
Therefore, 4×10⁵ moles of NaCl will react to produce = (4×10⁵ × 1)/2 = 2×10⁵ moles of Cl₂.
Thus, 2×10⁵ moles of Cl₂ were obtained from the reaction.
Finally, we shall determine the volume of Cl₂ produced. This can be obtained as follow:
1 mole of Cl₂ at stp = 22.4 dm³
Therefore,
2×10⁵ moles of Cl₂ at stp = 2×10⁵ 22.4
2×10⁵ moles of Cl₂ at stp = 4.48×10⁶ dm³
Thus, the volume of chlorine obtained from the reaction is 4.48×10⁶ dm³
