A current of 0.3 ampere flows through a 2-ohm resistor. At what rate does the resistor release heat?
1 answer:
Answer:
D. 018 W
Explanation:
Power = current × voltage
P = IV
From Ohm's law, voltage = current × resistance
V = IR
Therefore:
P = I²R
Given I = 0.3 A and R = 2 Ω:
P = (0.3 A)² (2 Ω)
P = 0.18 W
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