A current of 0.3 ampere flows through a 2-ohm resistor. At what rate does the resistor release heat?
1 answer:
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Answer:
The solution is given in the attachments.
Answer:
The question is incomplete, below is the complete question
"The real power delivered by a source to two impedance, Z1=4+j5Ω and Z2=10Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."
answer:
a. 615W, 384.4W
b. 17.4A
Explanation:
To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.
recall that the symbol for admittance is Y and express as
Hence for each we have,
for the second impedance we have
we also determine the voltage cross the impedance,
P=V^2(Y1 +Y2)
The real power in the impedance is calculated as
for the second impedance
b. We determine the equivalent admittance
We convert the equivalent admittance back into the polar form
the source current flows is