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Firdavs [7]
3 years ago
12

A current of 0.3 ampere flows through a 2-ohm resistor. At what rate does the resistor release heat?

Engineering
1 answer:
beks73 [17]3 years ago
6 0

Answer:

D. 018 W

Explanation:

Power = current × voltage

P = IV

From Ohm's law, voltage = current × resistance

V = IR

Therefore:

P = I²R

Given I = 0.3 A and R = 2 Ω:

P = (0.3 A)² (2 Ω)

P = 0.18 W

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