Answer:
8.85 Ω
Explanation:
Resistance of a wire is:
R = ρL/A
where ρ is resistivity of the material,
L is the length of the wire,
and A is the cross sectional area.
For a round wire, A = πr² = ¼πd².
For aluminum, ρ is 2.65×10⁻⁸ Ωm, or 8.69×10⁻⁸ Ωft.
Given L = 500 ft and d = 0.03 in = 0.0025 ft:
R = (8.69×10⁻⁸ Ωft) (500 ft) / (¼π (0.0025 ft)²)
R = 8.85 Ω
Answer:
the leader or organizer. you should have assigned jobs, so one of them should be in charge. if you did not assign jobs, assign them now, and one person has a job, and they must be held accountable. if they cannot do their job, someone might have to take over, but then you tell your prof. that they could not do their part, so hopefully you will get the credit you deserve and they will not.
Explanation:
Answer:
True
Explanation:
Tensile testing which is also referred to as tension testing is a process which materials are subjected to so as to know how well it can be stretched before it reaches breaking point. Hence, the statement in the question is true
Answer:
Frequency = 
Wavenumber = 
Energy = 
Energy = 1.4579 eV
Energy = 
Explanation:
As we are given the wavelength = 850 nm
conversion used : 
So, wavelength is 
The relation between frequency and wavelength is shown below as:

Where, c is the speed of light having value = 
So, Frequency is:


Wavenumber is the reciprocal of wavelength.
So,


Also,

where, h is Plank's constant having value as 
So,


Also,

So,


Also,

So,


1) 
2) 8.418
Explanation:
1)
The two components of the velocity field in x and y for the field in this problem are:


The x-component and y-component of the acceleration field can be found using the following equations:


The derivatives in this problem are:






Substituting, we find:

And

2)
In this part of the problem, we want to find the acceleration at the point
(x,y) = (-1,5)
So we have
x = -1
y = 5
First of all, we substitute these values of x and y into the expression for the components of the acceleration field:

And so we find:

And finally, we find the magnitude of the acceleration simply by applying Pythagorean's theorem:
