If the diameter of the bar is 0.490 at this load, determine I. the engineering stress and strain, and [2] II. the true stress and strain is 1561. 84 MPa.
<h3>What is strain?</h3>
Strain is a unitless degree of ways a great deal an item receives larger or smaller from an implemented load. Normal stress happens while the elongation of an item is in reaction to an everyday pressure (i.e. perpendicular to a surface), and is denoted via way of means of the Greek letter epsilon.
- L = 20 cm d x 1 = 0.21 cm
- dx 2 = 0.25 cmF=5500 a) σ= F/A1= 5000/(π/4x(0.0025)^2)= 1018.5916 MPa lateral stress= Ad/d1= (0.0021-0.0025)/0.0025 = - 0.1 longitudinal stress (ɛ_l)= -lateral stress/v = -(-0.16)/0.3
- (assuming a poisson's ration of 0.3) ε_l=0.16/0.3 = 0.5333
- b) σ_true= σ(1+ ɛ_I)= 1018.5916(1+0.5333
- = 1561.84 MPa.
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a) The flow capacity of the fan is 3150 L/min
d) the minimum diameter is 0.11 m
Explanation:
given data:
A = area of residence = 200 m²
h = height of building = 2.7 m
Percentage of air that must be replaced by fresh air is 35%
v = velocity of air in the duct = 5.5 m/s
a) The volume of the entire building is:
The flow capacity of the fan is equal to:
b) The volume flow rate of fresh air is equal to:
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2. contains a lot of gas and dust
3. is smaller than other types of galaxies
Answer:
Lay the person down and elevate thier legs slightly.
Explanation:
