Answer:
C. assembly line workers.
Explanation:
The purpose of having a ventilation system on board a motorized vessel is : To remove flammable gas from a vessel to avoid explosions.
<h3>Meaning of ventilation system</h3>
A ventilation system can be defined as a system that allows for removal of gases from a vessel to the atmosphere.
A Ventilation system is very important in every motorized vessel because they help to eliminate or remove flammable gases that are dangerous and are liable to explode when held in a large amount in the engine.
In conclusion, The purpose of having a ventilation system on board a motorized vessel is to remove flammable gas from a vessel their by avoiding explosions.
Learn more about Ventilation System: brainly.com/question/1687520
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Answer:
the overall heat transfer coefficient of this heat exchanger is 1855.8923 W/m²°C
Explanation:
Given:
d₁ = diameter of the tube = 1 cm = 0.01 m
d₂ = diameter of the shell = 2.5 cm = 0.025 m
Refrigerant-134a
20°C is the temperature of water
h₁ = convection heat transfer coefficient = 4100 W/m² K
Water flows at a rate of 0.3 kg/s
Question: Determine the overall heat transfer coefficient of this heat exchanger, Q = ?
First at all, you need to get the properties of water at 20°C in tables:
k = 0.598 W/m°C
v = 1.004x10⁻⁶m²/s
Pr = 7.01
ρ = 998 kg/m³
Now, you need to calculate the velocity of the water that flows through the shell:
![v_{w} =\frac{m}{\rho \pi (\frac{d_{2}^{2}-d_{1}^{2} }{4} )} =\frac{0.3}{998*\pi (\frac{0.025^{2}-0.01^{2} }{4}) } =0.729m/s](https://tex.z-dn.net/?f=v_%7Bw%7D%20%3D%5Cfrac%7Bm%7D%7B%5Crho%20%5Cpi%20%28%5Cfrac%7Bd_%7B2%7D%5E%7B2%7D-d_%7B1%7D%5E%7B2%7D%20%20%7D%7B4%7D%20%29%7D%20%3D%5Cfrac%7B0.3%7D%7B998%2A%5Cpi%20%28%5Cfrac%7B0.025%5E%7B2%7D-0.01%5E%7B2%7D%20%20%7D%7B4%7D%29%20%7D%20%3D0.729m%2Fs)
It is necessary to get the Reynold's number:
![Re=\frac{v_{w}(d_{2}-d_{1}) }{v} =\frac{0.729*(0.025-0.01)}{1.004x10^{-6} } =10891.4343](https://tex.z-dn.net/?f=Re%3D%5Cfrac%7Bv_%7Bw%7D%28d_%7B2%7D-d_%7B1%7D%29%20%7D%7Bv%7D%20%3D%5Cfrac%7B0.729%2A%280.025-0.01%29%7D%7B1.004x10%5E%7B-6%7D%20%7D%20%3D10891.4343)
Like the Reynold's number is greater than 10000, the regime is turbulent. Now, the Nusselt's number:
![Nu=0.023Re^{0.8} Pr^{0.4} =0.023*(10891.4343)^{0.8} *(7.01)^{0.4} =85.0517](https://tex.z-dn.net/?f=Nu%3D0.023Re%5E%7B0.8%7D%20Pr%5E%7B0.4%7D%20%3D0.023%2A%2810891.4343%29%5E%7B0.8%7D%20%2A%287.01%29%5E%7B0.4%7D%20%3D85.0517)
The overall heat transfer coefficient:
![Q=\frac{1}{\frac{1}{h_{1} }+\frac{1}{h_{2} } }](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B1%7D%7Bh_%7B1%7D%20%7D%2B%5Cfrac%7B1%7D%7Bh_%7B2%7D%20%7D%20%20%7D)
Here
![h_{2} =\frac{kNu}{d_{2}-d_{1}} =\frac{0.598*85.0517}{0.025-0.01} =3390.7278W/m^{2}C](https://tex.z-dn.net/?f=h_%7B2%7D%20%3D%5Cfrac%7BkNu%7D%7Bd_%7B2%7D-d_%7B1%7D%7D%20%3D%5Cfrac%7B0.598%2A85.0517%7D%7B0.025-0.01%7D%20%3D3390.7278W%2Fm%5E%7B2%7DC)
Substituting values:
![Q=\frac{1}{\frac{1}{4100}+\frac{1}{3390.7278} } =1855.8923W/m^{2} C](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B1%7D%7B4100%7D%2B%5Cfrac%7B1%7D%7B3390.7278%7D%20%20%7D%20%3D1855.8923W%2Fm%5E%7B2%7D%20C)
Answer:
power developed by the turbine = 6927.415 kW
Explanation:
given data
pressure = 4 MPa
specific enthalpy h1 = 3015.4 kJ/kg
velocity v1 = 10 m/s
pressure = 0.07 MPa
specific enthalpy h2 = 2431.7 kJ/kg
velocity v2 = 90 m/s
mass flow rate = 11.95 kg/s
solution
we apply here thermodynamic equation that
energy equation that is
![h1 + \frac{v1}{2} + q = h2 + \frac{v2}{2} + w](https://tex.z-dn.net/?f=h1%20%2B%20%5Cfrac%7Bv1%7D%7B2%7D%20%20%2B%20q%20%3D%20h2%20%2B%20%5Cfrac%7Bv2%7D%7B2%7D%20%20%2B%20w)
put here value with
turbine is insulated so q = 0
so here
![3015.4 *1000 + \frac{10^2}{2} = 2431.7 * 1000 + \frac{90^2}{2} + w](https://tex.z-dn.net/?f=3015.4%20%2A1000%20%2B%20%5Cfrac%7B10%5E2%7D%7B2%7D%20%20%3D%20%202431.7%20%2A%201000%20%2B%20%5Cfrac%7B90%5E2%7D%7B2%7D%20%20%2B%20w)
solve we get
w = 579700 J/kg = 579.7 kJ/kg
and
W = mass flow rate × w
W = 11.95 × 579.7
W = 6927.415 kW
power developed by the turbine = 6927.415 kW
Answer:
fluid nozzle that is too large