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4 years ago

Australia has 3 a’s but all pronounced differently how?

Physics

1 answer:

kobusy [5.1K]4 years ago

8 0

BecausE the first 'a' is used with a 'u' making a "ahh" sound

The second 'a' isn't paired with any other vowels so it's sound is a strong A sound

And the 'a' at the end is paired with an 'i' in front of it making an "ee-uhh" sound

plz rate me lol i tried <3

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Consider an object sliding at constant velocity along a frictionless surface. Which of the following best describes the forces o

Aliun [14]

-- The net vertical force on the object is zero.
Otherwise it would be accelerating up or down.

-- The net horizontal force on the object is zero.
Otherwise it would be accelerating horizontally,
that is, its 'velocity' would not be constant. That
would contradict information given in the question.

The total net force on the object is the resultant of the
net vertical component and net horizontal component.

Total net force = √(0² + 0²)

   = √(0 + 0)

   = √0

   = Zero.

The correct answer is the last choice on the list.

Also, you know what ! ? It doesn't even matter whether the surface it's
sliding on is frictionless or not.

If the object's velocity is constant, then the NET force on it must be zero.
If it's sliding on sandpaper, then something must be pushing it with constant
force, to balance the friction force, and make the net force zero. If the total
net force isn't zero, then the object would have to be accelerating ... either
its speed, or its direction, or both, would have to be changing.

3 0

3 years ago

A 0.0208 m diameter coin rolls up a 18.0◦ inclined plane. The coin starts with an initial angular speed of 56.0 rad/s and rolls

anastassius [24]

Answer:

h = 0.0259 m

Explanation:

given,

diameter of the cone = 0.0208 m

radius,r = 0.0104 m

angle of inclination,θ = 18°

initial angular velocity, ω_i = 56 rad/s

final angular velocity ,ω_f = 0 rad/s

height, h = ?

Rotational kinetic energy

$KE_r = \dfrac{1}{2}I\omega^2$

Moment of inertia of coin

$I = \dfrac{1}{2}MR^2$

so,

$KE_r = \dfrac{1}{4}MR^2\omega^2$

Transnational Kinetic energy

$KE_t = \dfrac{1}{2}Mv^2$

v = r ω

$KE_t = \dfrac{1}{2}MR^2\omega^2$

now,

using conservation energy

Kinetic energy of the coin is converted into the potential energy

KE_r + KE_t = PE

$\dfrac{1}{4}MR^2\omega^2 + \dfrac{1}{2}MR^2\omega^2 = Mgh$

$\dfrac{3}{4}R^2\omega^2=gh$

$\dfrac{3}{4}\times 0.0104^2\times 56^2=9.8\times h$

h = 0.0259 m

Vertical height gain by the coin is equal to 0.0259 m

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4 years ago

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Vaselesa [24]

Answer:

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3 years ago

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3 years ago

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denis23 [38]

The kelvin temperature/scale i think

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4 years ago