Question

What is the molarity of a solution that contains 9.63 grams of hcl in 1.5 liters of solution

Answer 1

Molar mass HCl = 36.5 g/mol

number of moles:

mass of solute / molar mass:

9.63 / 36.5 => 0.263 moles

Volume = 1.5 L

M = n / V

M = 0.263 / 1.5

M = 0.1753 mol/L

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Answer 2

Answer : The molarity of the solution is, 0.175 mole/L

Solution : Given,

Mass of HCl = 9.63 g

Molar mass of HCl = 36.5 g/mole

Volume of solution = 1.5 L

Molarity : It is defined as the number of moles of solute present in one liter of the solution.

Formula used :

$Molarity=\frac{\text{moles of solute}}{\text{Volume of solution in liters}}$

or,

$Molarity=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution in liters}}$

Now put all the given values in this formula, we get the molarity of the solution.

$Molarity=\frac{9.63g}{36.5g/mole\times 1.5L}=0.175mole/L$

Therefore, the molarity of the solution is, 0.175 mole/L