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Blababa [14]
3 years ago
6

What is the molarity of a solution that contains 9.63 grams of hcl in 1.5 liters of solution

Chemistry
2 answers:
Aleonysh [2.5K]3 years ago
8 0
Molar mass HCl = 36.5 g/mol

number of moles:

mass of solute / molar mass:

9.63 / 36.5 => 0.263 moles

Volume = 1.5 L

M = n / V

M = 0.263 / 1.5

M = 0.1753 mol/L

espero ter ajudado!
zavuch27 [327]3 years ago
4 0

Answer : The molarity of the solution is, 0.175 mole/L

Solution : Given,

Mass of HCl = 9.63 g

Molar mass of HCl = 36.5 g/mole

Volume of solution = 1.5 L

Molarity : It is defined as the number of moles of solute present in one liter of the solution.

Formula used :

Molarity=\frac{\text{moles of solute}}{\text{Volume of solution in liters}}

or,

Molarity=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution in liters}}

Now put all the given values in this formula, we get the molarity of the solution.

Molarity=\frac{9.63g}{36.5g/mole\times 1.5L}=0.175mole/L

Therefore, the molarity of the solution is, 0.175 mole/L

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What is the coefficient of silver in the final, balanced equation for this reaction?
katovenus [111]

Answer: 3

Explanation:

An oxide-reduction reaction or, simply, redox reaction, is a <u>chemical reaction in which one or more electrons are transferred between the reactants</u>, causing a change in their oxidation states, which is the hypothetical electric charge that the atom would have if all its links with different elements were 100% ionic.

For there to be a reduction-oxidation reaction, in the system there must be an element that yields electrons and another that accepts them:

  • The oxidizing agent picks up electrons and remains with a state of oxidation inferior to that which it had, that is, it is reduced.
  • The reducing agent supplies electrons from its chemical structure to the medium, increasing its oxidation state, ie, being oxidized.

To balance a redox equation you must <u>identify the elements that are oxidized and reduced and the amount of electrons that they release or capture, respectively. </u>

In the reaction that arises in the question the silver (Ag) is reduced <u>because it decreases its oxidation state from +1 to 0</u> and the aluminum (Al) is oxidized because <u>its oxidation state increases from 0 to +3</u>, releasing 3 electrons (e⁻). Then we can raise two half-reactions:

Ag⁺ + e⁻ → Ag⁰

Al⁰ → Al⁺³ + 3e⁻

In order to obtain the balanced equation, we must multiply the first half-reaction by 3 so that, when both half-reactions are added, the electrons are canceled. In this way:

(Ag⁺ + e⁻ → Ag⁰ ) x3

Al⁰ → Al⁺³ + 3e⁻               +

-------------------------------------

3Ag⁺ + Al⁰ → 3Ag⁰ + Al⁺³

So, the coefficient of silver in the final balanced equation is 3.

5 0
3 years ago
The chemical equation for the formation of ammonia is unbalanced.
ratelena [41]
Balance Chemical equation is as follow,

<span>                           3 H</span>₂ <span>(g) + N</span>₂ <span>(g)    </span>→<span>    2 NH</span>₃ <span>(g)

According to balanced equation, 3 Molecules (3 moles) of Hydrogen reacts with 1 Molecule of N</span>₂ to produce 2 moles (2 Molecules) of NH₃.

Result:
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7 0
3 years ago
(01.01 MC)
lys-0071 [83]

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8 0
4 years ago
Read 2 more answers
Calculate: (a) the weight (in lbf) of a 30.0 lbm object. (b) the mass in kg of an object that weighs 44N. (c) the weight in dyne
belka [17]

Answer:

a) 965,1 lbf

b) 4,5 kg

c) 1,33 * 10^6 dynes

Explanation:

Mass of an object refers to the amount of mattter it cotains, it can be expressed it gr, kg, lbm, ton, etc.

Weight of an object refers to a force, and is the measurement of the pull of gravitiy on an object. It may be definide as the mass times the acceleration of gravity.

                                        w=mg

In Planet Earth, the nominal "average" value for gravity is 9,8 m/s² (in the International  System) or 32,17 ft/s² (in the FPS system).

To solve this problem we'll use the following conversion factors:

1 lbf = 1 lbm*ft/s²

1 N = 1 kg*m/s²

1 dyne = 1 gr*cm/s²   and 1 N =10^5 dynes

1 ton = 907,18 kg

1 k = 1000 gr

a) m = 30 lbm

w = 30 lbm * 32,17 ft/s^{2} = 965, 1 \frac{lmb*ft}{s^{2} } = 965,1 lbf

b) w = 44 N

First, we clear m of the weight equation and then we replace our data.

m = \frac{w}{g} = \frac{44 N}{9,8 \frac{m}{{s}^{2}} } = 4,5 kg

c) m = 15 ton

m=15 ton * \frac{907,18 kg}{1 ton} = 13607,7 kg \\ w = mg = 13607,7 kg * 9,8 m/s2 = 133355,5 N * \frac{10^{5} dynes }{1 N} = 1,33 * 10^{6}dynes

4 0
4 years ago
A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to
Drupady [299]

Answer : The final temperature of the mixture is 29.6^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron = 0.499J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron = 39.9 g

m_2 = mass of water  = Density\times Volume=1g/mL\times 50.0mL=50.0g

T_f = final temperature of mixture = ?

T_1 = initial temperature of iron = 78.1^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC

T_f=29.6^oC

Therefore, the final temperature of the mixture is 29.6^oC

8 0
3 years ago
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