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horrorfan [7]
4 years ago
14

Question 5(Multiple Choice Worth 3 points)

Chemistry
1 answer:
Travka [436]4 years ago
8 0

Answer: B. Stay the same

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Calculate the volume in liters of a barium acetate solution that contains of barium acetate . Be sure your answer has the correc
Ilya [14]

Answer:

1.09 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:

100 g × (1 mol/255.43 g) = 0.391 mol

0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:

0.391 mol × (1 L/0.360 mol) = 1.09 L

5 0
4 years ago
Read 2 more answers
What is the mass of 3.00 moles of magnesium chloride, MgCl2? Express your answer with the appropriate units.
Tresset [83]
To answer this question you need to know how to calculate the molecular weight of a molecule. The compound is having 1 Mg atom and 2 Cl atom, thus the molecular weight should be: 
24.305+ 2*35.453= <span>95.211 gram/mol.

Then, the mass of 3 mol of MgCl would be:
3 mol * 95.211 gram/mol= 285.633 gram</span>
7 0
4 years ago
How many pounds of coal would you have to burn to generate enough heat to boil a 15 l kettle?
rjkz [21]
Note that
The heating value of standard coal is about 30,080 kJ/kg
1 L of water has a mass of 1.0 kg

The mass of 15 L of water = 15 kg.
The latent heat of vaporization of water is about 2260 kJ/kg,
 The energy required to boil 15 L of water is
(2260 kJ/kg)*(15 kg) = 33900 kJ

The mass of coal required to provide this energy is
(33900 kJ)/(30080 kJ/kg) = 1.127 kg

Because 1 kg = 2.205 lb, the mass of coal required is
(1.127 kg)*(2.205 lb/kg) = 2.485 lb

Answer: 2.49 lb (nearest hundredth)

7 0
3 years ago
The volume of an automobile air bag was 66.8 L when inflated at 25 °C with 77.8 g of nitrogen gas. What was the pressure in the
Ray Of Light [21]

Answer:

\large \boxed{\text{103 kPa}}

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 66.8 L

m = 77.8 g

T = 25 °C

Calculations:

(a) Moles of N₂

\text{Moles of N}_{2} = \text{77.8 g N}_{2} \times \dfrac{\text{1 mol N}_{2}}{\text{28.01 g N}_{2}} = \text{2.778 mol N}_{2}

(b) Convert the temperature to kelvins

T = (25 + 273.15) K = 298.15 K

(c) Calculate the pressure

\begin{array}{rcl}pV & =& nRT\\p \times \text{66.8 L} & = & \text{2.778 mol} \times \text{8.314 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 298.15 K}\\66.8p & = & \text{6886 kPa}\\p & = & \textbf{103 kPa}\end{array}\\\text{The pressure in the bag is $\large \boxed{\textbf{103 kPa}}$}

3 0
3 years ago
What charged particle is produced during ionic bonds
Setler79 [48]

Answer:

An ionic bond is formed by the complete transfer of some electrons from one atom to another. The atom losing one or more electrons becomes a cation or a positively charged ion. The atom gaining one or more electrons becomes an anion which is a negatively charged ion.

5 0
3 years ago
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