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RSB [31]
3 years ago
12

In the picture, what can you say about the indices of refraction n1 and n2? (1 point)

Physics
1 answer:
jeyben [28]3 years ago
8 0

Answer:

n1 = n2

Explanation:

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For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

5 0
3 years ago
Consider a sample containing 1.70 mol of an ideal diatomic gas.
babunello [35]

I don't know

because I don't know

7 0
3 years ago
a bullet is fired horizontally with a speed of 524 m/s from a height of 22m above the ground. calculate where it will hit the gr
lara31 [8.8K]

Given data:

* The height of the bullet is 22 m.

* The speed of bullet in the horizontal direction is 524 m/s.

Solution:

By the kinematics equation, the time taken by the bullet to reach the ground is,

h=u_yt+\frac{1}{2}gt^2

where u_y is the vertical velocity component, t is the time taken to reach the ground, g is the acceleration due to gravity, and h is the height of the bullet,

Substituting the known values,

\begin{gathered} 22=0+\frac{1}{2}\times9.8\times t^2 \\ t^2=\frac{22\times2}{9.8} \\ t^2=4.49 \\ t=2.12\text{ s} \end{gathered}

Thus, the time taken by the bullet to reach the ground is 2.12 seconds.

By the kinematics equation for the horizontal motion, the horizontal range of the bullet is,

R=u_xt+\frac{1}{2}at^2

where u_x is the horizontal component of the velocity, a is the acceleration along the horizontal direction, t is the time taken to reach the ground and R is the horizontal range,

Substituting the known values,

\begin{gathered} R=524\times2.12+0 \\ R=1110.9\text{ m} \end{gathered}

Thus, the horizontal range of the bullet is 1110.9 meters.

Hence, the bullet hit the ground at 1110.9 meters.

8 0
1 year ago
Which Law states Energy cannot be created or destroyed, energy can only change forms and be conserved
lisov135 [29]

Answer:

I believe that Law is called the Law of Conservation of Energy (Thermodynamics)

Explanation:

3 0
3 years ago
An object with a mass of 7 kg accelerates 5 m/s2 when an unknown force is applied to it. What is the unknown force?
Leto [7]

Answer:

35 N

Explanation:

Force, F = ma where m = mass = 7 kg and a = acceleration = 5 m/s².

So, F = ma = 7 kg × 5 m/s² = 35 N

4 0
3 years ago
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