Answer:
Net force = 250 N
Explanation:
Given that,
The mass of a teacher, m = 75 kg
As the parachute opens, the system experiences a 1000N drag.
We need to find the magnitude of net force acting on the teacher. 2 forces are acting on her i.e. drag force and weight.
Net force,
F = mg-D
= 75(10)-1000
= -250 N
Hence, the net force is 250 N and it is acting in the upward direction.
Explanation:
When neutral objects are placed in the vicinity of charged objects,they get attracted.
The isolated neutral object has positive charge and negative charge spread throughout it completely.
When a charged particle is brought,the opposite charges in the neutral object occupy the positions near to the charged particle and the like charges occupy the positions far from the charged particle.
This creates a dipole with some dipole moment.
This dipole attracts to the field of the charged particle.
Answer:
d. A projectile with a horizontal component of motion will have a constant horizontal velocity.
f. The horizontal velocity of a projectile is unaffected by the vertical velocity; these two components of motion are independent of each other.
g. The horizontal displacement of a projectile is dependent upon the time of flight and the initial horizontal velocity.
h. The final horizontal velocity of a projectile is always equal to the initial horizontal velocity.
Explanation:
When we are dealing with parabolic motion, the x-component of the velocity remains the same (hence, in the case of the horizontal component, the acceleration will always be zero), <u>while the y-component always change because it is affected by the acceleration due gravity that acts verticaly.</u>
On the other hand, the horizontal displacement
of the projectile is mathematically expressed as:
Where:
is the projectile's horizontal component of the initial velocity
is the time the parabolic motion lasts
This means <u>the projectile's horizontal displacement is directly proportional to the horizontal component of the initial velocity and the total time the projectile describes the parabolic motion</u>.
Of course, all of this considerations are assuming this is an ideal parabolic path and there is no air resistance.
Explanation:
Power=work done/time
=> 12kJ/6s = 12000J/6s = 2000W = 2kW.
hope this helps you
2Fe(s) + O2 -> 2FeO(s)
<span>2 'Fe' atoms on both sides </span>
<span>2 'O' atoms on both sides</span>