Answer:
inelastic collision.
Explanation:
An elastic collision consists in a collision in wich the bodies implied bounce off. Furthermore, the momentum of the bodies is conserved.
In as inelastic collision the momentum is not conserved, and is possible that the bodies implied in the collision stay joint after the collision.
In this case yo have that both bumper car and truck stayed joint after the collision. Hence, this situation is an inelastic collision.
Answer:
8.79 J
Explanation:
Given that a slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the bottom of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??
Total energy = mgh
Total energy = 4.41 × 2 = 8.82 J
Elastic potential energy = 1/2 × Ke^2
Elastic potential energy = 1/2 × 0.84 × 0.25^2
Elastic potential energy = 0.02625
Also,
Total energy = P.E + K.E
Substitute them into the formula above
8.82 = 0.02625 + K.E
K.E = 8.82 - 0.02625
K.E = 8.79375
K.E = 8.79 J
Therefore, the KINETIC ENERGY of the slinky at the bottom of the stairs is 8.79 Joules approximately
Answer:
Total mass of combination = 2+3+5 = 10kg.
Acceleration produced = 2m/s^2
hence force =( total mass × acceleration)= (2×10)= 20 N.
Net force on 3kg block = acceleration × mass = (2 × 2 )= 4 N
applied force on 2 kg block = 20N
Force between 2 kg and 3 kg block = (20-4) = 16N. ans
Net force on 3 kg block = 3 × 2 =6N.
Applied force on 3 kg block due to 2 kg block = 16N.
hence, force between 3 kg and 5 kg block = (16-6) = 10N .
answers:-
(a) 20 N
(b) 16N
(c) 10 N
The concept required to solve this problem is quantization of charge.
First the number of electrons will be calculated and then the total mass of the charge.
With these data it will be possible to calculate the percentage of load in the mass.
Here Q is the charge, n is the number of electrons and e is the charge on the electron
Replacing,
According to the quantization of charge the charge is defined as product of the number of electron and the charge on the electron
The total mass of the charge is
Here,
m = Mass of the charge
n = Number of electrons
= Mass of the electron
Replacing we have
Answer:
a
Generally from third equation of motion we have that
Here v is the final speed of the car
u is the initial speed of the car which is zero
is the initial position of the car which is certain height H
is the final position of the car which is zero meters (i.e the ground)
a is the acceleration due to gravity which is g
So
=>
b
Explanation:
Generally from third equation of motion we have that
Here v is the final speed of the car
u is the initial speed of the car which is zero
is the initial position of the car which is certain height H
is the final position of the car which is zero meters (i.e the ground)
a is the acceleration due to gravity which is g
So
=>
When we have that
=>
=>