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2 years ago

What is the simplest formula for a compound containing 0.50 mol na, 0.50 mol s, and 0.75 mol o?

1 answer:

7 0

We need to get the mole ratio between the elements. To do this, we will divide by the the smallest number of moles given as follows:
0.5 mole of Na / 0.5 = 1
0.5 mole of S / 0.5 = 1
0.75 mole of O / 0.5 = 3/2

Now, we need to get rid of the fractions. To do this, we will multiply all the ratios by 2:
Na = 1 x 2 = 2
S = 1 x 2 = 2
O = 3/2 x 2 = 3

So, in the simplest formula, the ratio Na:S:O is 2:2:3
This can be written as: Na2S2O3 which is known as sodium thiosulphate.

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The nucleus of an atom ok K-42 contains

horsena [70]

Number of proton K=19

so, 42 - 19 =23

then the answer in 19 protons and 23 neutrons

3 0

2 years ago

Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lith

alexandr402 [8]

The isotope that is more abundant, given the data is isotope Li7

<h3>Assumption</h3>

Let Li6 be isotope A
Let Li7 be isotope B

<h3>How to determine whiche isotope is more abundant</h3>

Molar mass of isotope A (Li6) = 6.02 u
Molar mass of isotope B (Li7) = 7.02 u
Atomic mass of lithium = 6.94 u
Abundance of A = A%
Abundance of B = (100 - A)%

Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]

6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]

6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]

6.94 = [6.02A% + 702 - 7.02A%] / 100

Cross multiply

6.02A% + 702 - 7.02A% = 6.94 × 100

6.02A% + 702 - 7.02A% = 694

Collect like terms

6.02A% - 7.02A% = 694 - 702

-A% = -8

A% = 8%

Thus,

Abundance of B = (100 - A)%

Abundance of B = (100 - 8)%

Abundance of B = 92%

SUMMARY

Abundance of A (Li6) = 8%
Abundance of B (Li7) = 92%

From the above, isotope Li7 is more abundant.

Learn more about isotope:

brainly.com/question/24311846

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4 0

1 year ago

25. How many ml of a .0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid?

Mariana [72]

Answer: There are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

Explanation:

Given: $M_{1}$ = 0.0023 M, $V_{1}$ = ?

$V_{2}$ = 15.0 mL, $M_{2}$ = 0.012 M

Formula used to calculate volume of strontium hydroxide solution is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.0023 M \times V_{1} = 0.012 M \times 15.0 mL\\V_{1} = 78.26 mL$

Thus, we can conclude that there are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

8 0

2 years ago

If a 45 mM phosphate solution(solution A) had an absorbance of 1.012. What would be the absorbance if 11 mL of solution A was us

timofeeve [1]

Answer:

0.550

Explanation:

The absorbance (A) of a substance depends on its concentration (c) according to Beer-Lambert law.

A = ε . <em>l</em> . c

where,

ε: absorptivity of the species

<em>l</em>: optical path length

A 45 mM phosphate solution (solution A) had an absorbance of 1.012.

A = ε . <em>l</em> . c

1.012 = ε . <em>l</em> . 45 mM

ε . <em>l</em> = 0.022 mM⁻¹

We can find the concentration of the second solution using the dilution rule.

C₁ . V₁ = C₂ . V₂

45mM . 11mL = C₂ . 20.0 mL

C₂ = 25 mM

The absorbance of the second solution is:

A = (ε . <em>l</em> ). c

A = (0.022 mM⁻¹) . 25 mM = 0.55 (rounding off to 3 significant figures = 0.550)

8 0

2 years ago

Which of the following is likely to have the lowest viscosity? hot oil room temperature oil room temperature water below room te

zzz [600]

Viscosity, is a state of matter where it resists flow or may be in thick semifluid form because of friction acting inside the matter.In this case, hot oil room temperature would lessen the viscosity of the oil (animal oil). Thank you for your question. Please don't hesitate to ask in Brainly your queries.

4 0

2 years ago

Read 2 more answers