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alexgriva [62]
3 years ago
13

Every object that has mass attracts every other object with a gravitational force. It has been proven that the size of the gravi

tational force increases as the objects’ masses increase but graviational force decreases rapidly as the distance between the objects increases.
This statement about matter and its behavior is best classified as a______.
Physics
2 answers:
Blababa [14]3 years ago
7 0
Newton's law of universal gravitation
Anna [14]3 years ago
3 0

Explanation:

The gravitational force increases as the mass of the object increases and it rapidly decreases as the distance between the objects increases. This statement is best classified as the law of universal gravitation.

Two objects having mass attracts every other object with a gravitational force. It is given by :

F=G\times \dfrac{m_1\times m_2}{r^2}..........(1)

From equation (1), it is clear that the force is directly proportional to the product of masses and inversely proportional to the distance between them.  It is "universal law of gravitation".

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Damm [24]

Answer:

595433.00

1456543.00

Explanation:

7 0
3 years ago
3m/s for 12 seconds how dar would he walk
Sunny_sXe [5.5K]
I think 36m/12s because 3×12 =36
4 0
3 years ago
Rod AB has a diameter of 200mm and rod BC has a diameter of 150mm. Find the required temperature increase to close the gap at C.
Leni [432]

Answer:

T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}

Explanation:

The given data :-

  • Diameter of rod AB ( d₁ ) = 200 mm.
  • Diameter of rod BC ( d₂ ) = 150 mm.
  • The linear co-efficient of thermal expansion of copper ( ∝ ) = 1.6 × 10⁻⁶ /°C
  • The young's modulus of elasticity of copper ( E ) = 120 GPa = 120 × 10³ MPa.
  • Consider the required temperature increase to close the gap at C = T °C
  • Consider the change in length of the rod = бL

Solution :-

\begin{aligned}\sum H& =0\\-R_A+R_C&=0\\R_A&=R_C\\R_A&=R\\R_C&=R\\R_{A}&=\text{reaction\:force\:at\:A}\\R_{C}&=\text{reaction\:force\:at\:C}\\\sigma_{AB}&=\text{axial\:stress\:at\:A}\\\sigma_{BC}&=\text{axial\:stress\:at\:B}\\\sigma_{AB}&=\frac{R}{A_{A}}\\&=\frac{R_{A}}{A_{A}}\\\sigma_{BC}&=\frac{R_{B}}{A_{B}}\\&=\frac{R}{A_{B}}\\\frac{\sigma_{AB}}{\sigma_{BC}}&=\frac{A_{B}}{A_{B}}\\&=\frac{\frac{\pi}{4}\cdot 150^{2}}{\frac{\pi}{4}\cdot 200^{2}}\\&=\frac{9}{16}\end{aligned}

\begin{aligned}\delta L&= (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\0& = (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\&=\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{AB}+\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{BC}\\&=2\:\alpha\:T\:L-\frac{L}{E}(\sigma_{AB}+\sigma_{BC})\\T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}\end{aligned}

5 0
3 years ago
A conservative force does the same work regardless of the path taken.
ella [17]

A conservative force is a force that when work is done against this force the work done does not depend on the path taken only the initial and final position.

5 0
3 years ago
Read 2 more answers
I NEED THIS ASAP!!! A ball is thrown straight up with an initial velocity of 4.40 m/s. Assuming there is no air friction, what i
Lilit [14]

Answer:

I think it is 80m/s

Explanation:

d = ½ g t2

  = ½ (10 m/s2) (4 s)2

  = (5 m/s2) (16 s2)

  = 80 ms

75% sure

Hope this helps!!!

5 0
3 years ago
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