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AleksandrR [38]
3 years ago
13

A charge of 4.5x10^-5 C is placed in an electric field with a strength of 2.0x10^4 N/C. What is the electric force acting on the

charge?
Physics
1 answer:
Alex3 years ago
6 0

Answer:

0.9 N

Explanation:

The electric force acting on a charge is given by:

F=qE

where

q is the magnitude of the charge

E is the strength of the electric field

In this problem, we have

q=4.5\cdot 10^{-5}C is the charge

E=2.0\cdot 10^4 N/C is the strength of the electric field

Substituting into the equation, we find

F=(4.5\cdot 10^{-5}C)(2.0\cdot 10^4 N/C)=0.9 N

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<h3>How we compare the flow of electricity to water?</h3>

Water flowing in pipes is like flowing of electricity in a circuit. A battery is like a pump from where electricity comes and moves in the circuit. Electrons flowing through wires are like water molecules flowing through pipes. So in comparison between water and electricity, both water and electricity are similar to each other in flowing and movement.

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