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AleksandrR [38]

3 years ago

13

A charge of 4.5x10^-5 C is placed in an electric field with a strength of 2.0x10^4 N/C. What is the electric force acting on the

charge?

1 answer:

Alex3 years ago

6 0

Answer:

0.9 N

Explanation:

The electric force acting on a charge is given by:

$F=qE$

where

q is the magnitude of the charge

E is the strength of the electric field

In this problem, we have

$q=4.5\cdot 10^{-5}C$ is the charge

$E=2.0\cdot 10^4 N/C$ is the strength of the electric field

Substituting into the equation, we find

$F=(4.5\cdot 10^{-5}C)(2.0\cdot 10^4 N/C)=0.9 N$

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