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MAXImum [283]
3 years ago
10

Relative density has no unit .why ?​

Physics
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Relative density is a ratio of the density of a certain material to the density of a reference material. Relative density has no unit, because the units of the material in question cancel out with the units of the reference material. For example, say a cooking oil’s density is 0.9 g/cm^3.

Explanation:

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While ionic bonds join metals to nonmetals, and covalent bonds join nonmetals to nonmetals, metallic bonds are responsible for the bondingbetween metal atoms. In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize.

I hope that this answer helps you out
7 0
3 years ago
How much time does it take 9,560 joules of work with 860 watts of power
tia_tia [17]

Explanation:

use equation power=watts/time

to find time rearrange to make time = power/wats

so you have your equation substitute the numbers

so 9560J/860W is 11 minutes

5 0
3 years ago
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Creates an image that appears upside down behind the focal point
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8 0
3 years ago
A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q
Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges q_1 and q_2 separated by a distance d, the magnitude of the electrostatic force F between them is:

F = k \frac{|q_1q_2|}{d^2}

where k is Coulomb's constant.

Taking the values:

d = 4.6 \ 10^{-15} m

q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}

and knowing the value of the Coulomb's constant:

k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}

Taking all this in consideration:

F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}

F = 120.85  \ N

8 0
3 years ago
What will happen to the 0.1 N force if one charges is increased by a factor of 3?
AleksandrR [38]

Answer:

Explanation:

Force between two charges is given by the following expression

F = \frac{KQ_1Q_2}{d^2}  Q₁ and Q₂ are two charges and d is distance between two.

.1 = \frac{KQ_1Q_2}{d^2}

If Q₁ becomes three times , force will become 3 times . Hence force becomes .3 N in the first case.

Force F = .3 N

If charge becomes one fourth , force also becomes one fourth .

F= \frac{.1}{4}

= .025 N.

5 0
2 years ago
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